All categories

2 years ago

3x+1+5x=7+15+7x what is x?

Mathematics

2 answers:

Dahasolnce [82]2 years ago

8 0

Answer:

X= 21

Step-by-step explanation:

First you want to add alike terms which will get you 8x+1=22+7x. Next you want to get your x on one side so I subtracted 7x which you get x+1=22. Last you want to get rid of your 1 to get x alone so you subtract 1 from both sides and you get x=21.

baherus [9]2 years ago

4 0

Answer:

Step-by-step explanation:

3x + 1 + 5x = 7 + 15 + 7x <em>combine like terms</em>

(3x + 5x) + 1 = (7 + 15) + 7x

8x + 1 = 22 + 7x <em>subtract 1 from both sides</em>

8x = 21 + 7x <em>subtract 7x from both sides</em>

x = 21

You might be interested in

$84 increased by 120 percent

Elanso [62]

$\rm 84+120\% \\ \\ 84+ \frac{12\not0\cdot84}{10\not0}= \\ \\ 84+ \frac{1008}{10}= \\ \\ 84+100,8=\\ \\ \bold{184,8\$}$

5 0

2 years ago

Solve for x: a(x+b)-c=d

tankabanditka [31]

D=ab-c Theres your answer
a-1<span />

7 0

3 years ago

(-3)-(-19) I got -22 am I right?

N76 [4]

Answer:

Step-by-step explanation:

the negative outside the parenthesis removes the negative that is with the 19 and it is going to be 19-3 which equal 16

4 0

3 years ago

Read 2 more answers

Line FG goes through the points (4,9) and (1,3). Which equation represents a line that is perpendicular to FG and passes through

stiks02 [169]

Answer:

$x + 2y= 2$

Step-by-step explanation:

Given

Points:

$F = (4,9)$

$G = (1,3)$

Required

Determine the equation of line that is perpendicular to the given points and that pass through $(2,0)$

First, we need to determine the slope, m of FG

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where

$F = (4,9)$ --- $(x_1,y_1)$

$G = (1,3)$ --- $(x_2,y_2)$

$m = \frac{3 - 9}{1 - 4}$

$m = \frac{- 6}{- 3}$

$m =2$

The question says the line is perpendicular to FG.

Next, we determine the slope (m2) of the perpendicular line using:

$m_2 = -\frac{1}{m}$

$m_2 = -\frac{1}{2}$

The equation of the line is then calculated as:

$y - y_1 = m_2(x - x_1)$

Where

$m_2 = -\frac{1}{2}$

$(x_1,y_1) = (2,0)$

$y - 0 = -\frac{1}{2}(x - 2)$

$y = -\frac{1}{2}(x - 2)$

$y = -\frac{1}{2}x + 1$

Multiply through by 2

$2y = -x + 2$

Add x to both sides

$x + 2y= -x +x+ 2$

$x + 2y= 2$

Hence, the line of the equation is $x + 2y= 2$

8 0

3 years ago

Read 2 more answers

Find the complex zeros of each polynomial function. Use your results to write the polynomial as a product of linear factors. Tha

mart [117]

here you are the answer.

7 0

8 months ago