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Dovator [93]
3 years ago
9

Write eighteen hundredths as a decimal. P.S. dont put nothing stupid , just answer .

Mathematics
1 answer:
pishuonlain [190]3 years ago
4 0

Eighteen hundredths as a decimal is 0.18

<h3><u>Solution:</u></h3>

We have to find eighteen hundredths as a decimal

Eighteen hundredths means 18 over one hundred

We have to write 18 over one hundred as decimal

A decimal is a fraction written in a special form

Let us first write 18 over one hundred in fraction form

Eighteen hundredths = 18 over one hundred

\rightarrow \frac{18}{100}

Now divide 18 by 100 to get the decimal form

\rightarrow \frac{18}{100} = 0.18

Thus the eighteen hundredths as a decimal is 0.18

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Answer:

y'= \frac{3x+2}{2\sqrt{x} }

General Formulas and Concepts:

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

y=\sqrt{x} (x+2)

<u>Step 2: Rewrite</u>

y=x^{\frac{1}{2} } (x+2)

<u>Step 3: Differentiate</u>

  1. Product Rule [Basic Power/Chain Rule]:                 y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)
  2. Simplify:                                                                            y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}
  3. Rewrite:                                                                                        y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}
  4. Add:                                                                                                       y'= \frac{3x+2}{2\sqrt{x} }
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Step-by-step explanation:

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Just work this problem out backwards. First write out an equation.
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Now solve :

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