Answer:
17.15 m/s.
Explanation:
The following data were obtained from the question:
Maximum height (h) = 15 m
Final velocity (v) = 0 m/s
Acceleration due to gravity (g) = –9.8 m/s² (since the ball is going again gravity)
Initial velocity (u) =.?
The initial velocity with which the baseball pitcher threw the ball can be obtained as follow:
v² = u² + 2gh
0² = u² + (2 × –9.8 × 15)
0 = u² + (–294)
0 = u² – 294
Collect like terms
0 + 294 = u²
294 = u²
Take the square root of both side
u = √294
u = 17.15 m/s
Therefore, the baseball pitcher threw the ball with an initial velocity of 17.15 m/s
