Answer:
(a) the deceleration of the player is -80.36 m/s²
(b) the time the collision last is 0.093 s
Explanation:
Given;
Initial velocity of the football player, u = 7.50 m/s
Final velocity of the football player, v = 0
distance traveled = compression of the pad, s = 0.35 m
Part (a) the deceleration of the player
v² = u² + 2as
0 = 7.5² + (2 x 0.35)a
0 = 56.25 + 0.7a
- 56.25 = 0.7a
a = -56.25 / 0.7
a = -80.36 m/s²
Part (b) the time the collision last
v = u + at
t = (v - u)/a
t = (0 - 7.5)/ -80.36
t = - 7.5 / -80.36
t = 0.093 s
Answer:
1.884 meters per second
Explanation:
s = d/t
d = C = 2πr = 2π(6) = 37.68 m
t = 20 s
s = (37.68 m)/(20 s)
s = 1.884 m/s
D), because the roller coaster it's falling, therefore, losing height, but gaining velocity
The focus of an earthquake is internal and is harder to record than the waves of an epicenter, which are on the surface.
