Question

Please guys I want your help, there is 20p point

Answer 1

Answers:

The acceleration due to gravity on the surface of earth is 9.8 ms^(-2).Time period of a simple pendulum on earth and moon are 3.5 second and 8.4 second respectively. Find the acceleration due to gravity on the moon .
Hint : T_(e) = 2pi sqrt((L)/(g_(e))) T_(m)= 2pi sqrt((L)/(g_(m)))
(T_(e)^(2))/(T_(m)^(2))= (g_(m))/(g_(e))
g_(m) = (T_(e)^(2))/(T_(m)^(2))g_(e)