Answer:
<h2>10.52 kg</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
f is the force
a is the acceleration
From the question we have
We have the final answer as
<h3>10.52 kg</h3>
Hope this helps you
Answer: 24.1 mL
Explanation:
Initial volume V1 = 65 mL
Initial pressure P1 = 0.854 atm
Final volume of the gas V2 = ?
Final pressure of the gas P2 = 2.3 atm
Since, pressure and volume are involved while temperature is constant, apply the formula for Boyle's law
P1V1 = P2V2
0.854 atm x 65 mL = 2.3 atm x V2
55.51 atm mL = 2.3 atm x V2
V2 = (55.51 atm mL / 2.3 atm)
V2 = 24.1 mL
Thus, the final volume of the gas will be
24.1 mL
The two displacement functions are
x₁ = 4t
x₂ = -161 + 48t - 4t²
where
x₁, x₂ are in meters
t is time, s
The distance between the two objects is
x = x₁ - x₂
= 4t + 161 - 48t + 4t²
x = 4t² - 44t + 161
Write this equation in the standard form for a parabola.
x = 4[t² - 11t] + 161
= 4[ (t - 5.5)² - 5.5² ] + 161
x = 4(t-5)² + 40
Ths is a parabola that faces up and has its vertex (lowest point) at (5, 40).
Therefore the closest approach of the two objects is 40 m.
The graph of x versus t confirms the result.
Answer: The distance of the closest approach is 40 m.
Answer:
A first-class lever: fulcrum is between input and output force; second-class lever: output force is between input force and fulcrum; third-class lever: input force is between fulcrum and output force