Answer:
<em>n =1.33 revolutions</em>
Explanation:
<u>Uniform Circular Motion</u>
The angular speed can be calculated in two different ways:
Where:
v = tangential speed
r = radius of the circle described by the rotating object
Also:
Where:
f = frequency
Solving for f:
Since the frequency is calculated when the number of revolutions n and the time t are known:
We can solve for n:
n=f.t
The particle moves in a circle of r=90 m with a speed v=25 m/s. Thus the angular speed is:
Now we calculate f:
Calculating the number of revolutions:
n = 0.04421*30
n =1.33 revolutions
Answer:
Explanation:
The approach of Linear expansivity was used in solving the problem and the detailed steps and appropriate calculation is carefully shown in the attached file.
Answer:
Potential Energy stored = mgh ; m : mass, g : gravitational acceleration (let 10m/s) , h : height
Hence,
Energy Stored in the ball = mgh = (2*10*4) J
= 80 Joules!
Answer: B. It demonstrates a behavior or particles.
Explanation: I took the test and got it right
For simplicity, assume that the total mass of the compound is 100 g.
Therefore, by mass
Ca = 24.7 g, H = 1.2 g, C = 14.8 g, and O = 59.3 g
Converting these to moles
Mol = mass*1/atomic mass
Ca = 24.7*1/40.078 =0.6163 mol Ca
H = 1.2*1/1.01 = 1.1881 mol H
C = 14.8*1/12.01 = 1.2323 mol C
O = 59.3/16 = 3.7062 mol O
Next, divide all the mols by the smallest value obtained.
Ca: 0.6163/0.6163 = 1 mol Ca
H: 1.1881/0.6163 = 2 mol H
C: 1.2323/0.6163 = 2mol C
O: 3.7062/0.6163 = 6 mol O
Therefore, empirical formula of the compound is
CaH2C2O6
This compound is referred to as Calcium Bicarbonate
