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Sonja [21]
3 years ago
15

Select all the ways the rectangle could have been rotated to get from Frame 1 to Frame 2. 40 degrees clockwise 40 degrees counte

rclockwise 90 degrees clockwise 90 degrees counterclockwise 140 degrees clockwise 140 degrees counterclockwise Lesson 3
Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0

Answer:

40 degrees clockwise

140 degrees counterclockwise

Step-by-step explanation:

The rectangle is rotated in Figure B. The angle of rotation is 40 degrees. If we rotate a rectangle at an angle of 40 degrees clockwise then wit will be at the position as shown in figure B. The 90 degrees angle is perpendicular angle. Rectangle will not reach the desired position. If we rotate the rectangle at 140 degrees counterclockwise this will be the figure B representation. The rotation to 90 degree counterclockwise is either not suitable for the desired rectangle position.

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aev [14]

Answer:

whats the question?

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP!!! very confused
Leni [432]

Answer:

Step-by-step explanation:

The vertices lie on the x-axis, as is determined by their coordinates. This makes the center of this hyperbola (0, 0) because the center is directly between the vertices. The fact that the foci also lie on the x-axis tells us that this is the main axis. What this also tells us is which way the hyperbola "opens". This one opens to the left and the right as opposed to up and down. The standard form for this hyperbola is:

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1 and so far we have that h = 0 and k = 0.

By definition, a is the distance between the center and the vertices. So a = 5, and a-squared is 25. So we're getting there. Now here's the tricky part.

The expressions for the foci are (h-c, k) and (h+c, k). Since we know the foci lie at +/-13, we can use that to solve for c:

If h+c = 13 and h = 0, then

0 + c = 13 and c = 13.

We need that c value to help us find b:

c^2=a^2+b^2 and

13^2=5^2+b^2 and

169=25+b^2 and

144=b^2 so

b = 12. Now we're ready to fill in the equation:

\frac{x^2}{25}-\frac{y^2}{144}=1 and there you go!

3 0
3 years ago
Four to the sixth power times four to the -8th power please explain how to do this I don't understand it
Alenkinab [10]
Your question equals 1/16 or 0.0625.
6 0
3 years ago
What's the volume of a pipe that's 4 feet in diameter and 24 feet long? (Use π = 3.1416.)
Karolina [17]

Answer:

301.5936 cubic ft

Step-by-step explanation:

Formula for the volume of a cylinder is V = pi*r*r*h, where r represents the radius and h represents the height of the cylinder. Since radius is half the length of diameter, the pipe has a radius of 4/2 = 2 ft.

V = pi*r*r*h = 3.1416*2*2*24 = 301.5936 cubic ft

5 0
2 years ago
cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0
Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder=2\pi rh

Area of circular base=Area of circular top=\pi r^2

Total cost,C(r)=0.02\times 2\pi rh+2\pi r^2\times 0.07

Volume of cylinder,V=\pi r^2 h

200=\pi r^2 h

h=\frac{200}{\pi r^2}

Substitute the value of h

C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07

C(r)=\frac{8}{r}+0.14\pi r^2

Differentiate w.r.t r

C'(r)=-\frac{8}{r^2}+0.28\pi r

C'(r)=0

-\frac{8}{r^2}+0.28\pi r=0

0.28\pi r=\frac{8}{r^2}

r^3=\frac{8}{0.28\pi}=9.095

r=(9.095)^{\frac{1}{3}}=2.09

Again, differentiate w.r.t r

C''(r)=\frac{16}{r^3}+0.28\pi

Substitute the value of r

C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0

Therefore,the product cost is minimum at r=2.09

h=\frac{200}{\pi (2.09)^2}=14.57

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0
3 years ago
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