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Sav [38]
3 years ago
7

Help me please help ASAP please I will mark brainliest if I can

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer:

60-9pi if you need that rounded then 31.73

Step-by-step explanation:

10*6= 60

the two semi circles make one full circle. a circle formula is pi*r^2 = pi*3^2= 9pi

then subtract 9pi from 60

60-9pi = 31.73

Bingel [31]3 years ago
4 0

Answer:

31.8

Step-by-step explanation:

60-28.2 = 31.8

You might be interested in
Compare partial products and regrouping
Stella [2.4K]

Let us first describe how partial product and regrouping are alike:

Partial Products and Regrouping are alike because both methods are multiplied by one number and if the product of the number has 2 digits it can be carried.

Now let us discuss how they are different:

Partial Products and Regrouping are different because Partial Products are doing multiplication step by step and regrouping is regular multiplication.

Hope it helps.

5 0
3 years ago
I need to simplify √(5+2√2) and √(6+2√5)
SIZIF [17.4K]
This expression is easier than it looks like. I thought that to solve it you have for example to express the 2 via 10 * 5^-1 and stuff like that - but you can multiply and divide this expression by some factor. In our case first we multiply by conjunctive expression root(5-2root2) and the second by root(6+2root5). In first we get root16 and the second calculate.
6 0
3 years ago
What is the slope of the line that passes through the points (1, 1) and (9,7)?
Zarrin [17]
The answer is 3/4.

Step-By-Step Explanation

Slope Formula:m=y2-y1/x2-x1
Substitute: 7-1/9-1
Answer: 3/4
5 0
3 years ago
Acellus
ss7ja [257]

Answer:

AB = 3.6

Step-by-step explanation:

Given

The attached graph

Required

Distance AB

From the graph:

A = (-2,1)

B = (1,-1)

The distance is:

AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

AB = \sqrt{(-2 -1)^2 + (1- -1)^2}

AB = \sqrt{(-2 -1)^2 + (1+1)^2}

AB = \sqrt{13}

AB = 3.6

6 0
3 years ago
First time on Brainly! Please Help!!!!! >^<
lys-0071 [83]
Welcome to Brainly!

Binomial Theorem will follow this pattern:
The powers start at 3 and decrease down to 0 for the first term,
and start at 0 and increase to 3 for the other term.

(2x+4)^3 =

\rm \_\_(2x)^34^0+\_\_(2x)^24^1+\_\_(2x)^14^2+\_\_(2x)^04^3

See how the power counts down on the (2x)
and counts up on the 4?
That's the pattern that our expansion must follow.

I left a little space in front of each term.
The coefficient in front of each term will come from the fourth row of Pascal's Triangle. The one that looks like this:

1 3 3 1

Those are the coefficients we want:

\rm 1(2x)^34^0+3(2x)^24^1+3(2x)^14^2+1(2x)^04^3

We can clean this up a little bit by getting rid of some of the junk. Anything to the 0th power is 1. So let's suppress all of our 1's because multiplying by 1 is not important.

\rm (2x)^3+3(2x)^24+3(2x)4^2+4^3

Now apply exponent rule, distributing the power to both the 2 and the x where applicable.

\rm 2^3x^3+3\cdot2^2x^24+3\cdot2x4^2+4^3

Remember, multiplication is COMMUTATIVE, meaning we can multiply things in any order. So let's bring the numerical portion to the front of each term and multiply it all out.

\rm 2^3x^3+3\cdot2^2\cdot4x^2+3\cdot2\cdot4^2x+4^3
\rm 8x^3+48x^2+96x+64
6 0
3 years ago
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