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UkoKoshka [18]
3 years ago
9

Enter the fraction as a sum of unit fractions.3/18=18/blank+18/blank+18/blank help pls

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
5 0

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wtjfavyw

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I need to figure out how many solutions does the system of equations below have.
Aleonysh [2.5K]

Answer:

The system has one solution.

Step-by-step explanation:

To find the number of solutions of the system, we equal both equations for y.

If we have ax = b, in which both a and b are different of 0, we have one solution.

If both a and b are 0, we have infinite solutions.

If a is 0 and b is not, there are no solutions.

y=6/7x-8 and y=7/9x+10/9

So

\frac{6x}{7} - 8 = \frac{7x}{9} + \frac{10}{9}

\frac{6x}{7} - \frac{7x}{9} = \frac{10}{9} + 8

\frac{54x - 49x}{63} = \frac{10}{9} + \frac{72}{9}

\frac{5x}{63} = \frac{82}{9}

45x = 63*82

Both a and b are different of 0, so the system has one solution.

6 0
2 years ago
Find the values of the variables and the measures of the angles
yuradex [85]

Answer:

x = 13

39° and 51°

Step-by-step explanation:

Angles in a triangle add up to 180 degrees.

This is a right angle triangle, so one side has a size of 90 degrees.

3x + 4x - 1 + 90 = 180

7x + 89 = 180

7x = 91

x = 91/7

x = 13

Put x as 13 to work out the size of the angles.

3(13) = 39

4(13) - 1

52 - 1 = 51

8 0
2 years ago
Read 2 more answers
An automobile company hired an advertising agency to survey its customers to find out which brand of tire they preferred for the
alexandr1967 [171]
A:the mean and that’s all I know ahahahahahahahhbbahhhh
7 0
3 years ago
Read 2 more answers
Use the Pythagorean theorem to find the unknown side of the right<br>triangle​
kramer

Answer:

26

Step-by-step explanation:

→ Utilise Pythagoras theorem

a² + b² = c²

→ Substitute in the values

10² + 24² = c²

→ Simplify

100 + 576 = c²

→ Simplify further

676 = c²

→ Square root both sides to isolate c

26 = c

7 0
3 years ago
In ADEF, the measure of
MrMuchimi

Answer:

X= 51.71

You can use a protractor

6 0
3 years ago
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