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nydimaria [60]
3 years ago
7

The specifications for the diameter of a molded part are 10 mm ± 0.5 mm. The actual average and standard deviation from 250 part

s sampled is 10.1 mm and 0.1 mm, respectively. The process can be characterized as:
Mathematics
1 answer:
ad-work [718]3 years ago
5 0

Answer: Capable

Step-by-step explanation: The capability of a process could be exaplained as a measure of the ability of a process to produce part within specified limits by making use of statistical measurement. In determining if a certain process is capable or not, the value of process capability (Cp) is measured, in most cases, a process is deemed capable by having a Cp value of 1.33 or higher.

Cp formula :

(Upper specification limit(USL) - Lower specification limit(LSL) ) / 6* standard deviations

Diameter = 10 mm ± 0.5 mm

Standard deviation = 0.1mm

USL = 10 + 0.5 = 10.5

LSL = 10 - 0.5 =. 9.5

Cp = (10.5 - 9.5) / 6*0.1

Cp = 1/0.6

Cp = 1.6666

Cp = 1.67

Hence, the process is capable

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Given: sin(18m-12)=cos(7m+2), find the value of m.
V125BC [204]

Answer:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

Step-by-step explanation:

Solve for m:

-cos(7 m + 2) sin(12 - 18 m) = 0

Multiply both sides by -1:

cos(7 m + 2) sin(12 - 18 m) = 0

Split into two equations:

cos(7 m + 2) = 0 or sin(12 - 18 m) = 0

Take the inverse cosine of both sides:

7 m + 2 = π n_1 + π/2 for n_1 element Z

or sin(12 - 18 m) = 0

Subtract 2 from both sides:

7 m = -2 + π/2 + π n_1 for n_1 element Z

or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or 12 - 18 m = π n_2 for n_2 element Z

Subtract 12 from both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

3 0
3 years ago
What is (4c-d+0.2)^2-10c; c=3.1, d=4.6​
yuradex [85]

Good evening ,

______

Answer:

(4c-d+0.2)² - 10c = 33

___________________

Step-by-step explanation:

(4c-d+0.2)^2-10c

c=3.1, d=4.6​

(4(3.1) - 4.6 + 0.2)² - 10(3.1) = (12.4 - 4.6 + 0.2)² - 31 = (7.8 + 0.2)² -31 = 8² - 31 = 64-31 =33.

:)

8 0
3 years ago
Read 2 more answers
A group of 100 students took a quiz. Their average score was 76 points. If the average score for the boys was 80 points and the
sveta [45]

Answer:

The number of girls participated in quiz is 40 .

Step-by-step explanation:

Given as :

Total number of students took quiz = 100

Average score of 100 students = 76 points

The Average score of boys = 80 points

The Average score of girls = 70 points

Let The number of boys participated in quiz = b

Let The number of girls participate in quiz = g

Now, According to question'

Total number of students took quiz = number of boys participated in quiz + number of girls participated in quiz

Or, b + g = 100           ........A

<u>Again</u>

∵ Average score of 100 students = 76 points

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So, Average score of boys × number of boys participated + Average score of girls × number of girls participated = Total score of 100 students

Or, b × 80 + g × 70 = 7600

Or, 80 b + 70 g = 7600             .........B

Now, Solving equation A and B

(80 b + 70 g ) - 70 ×( b + g ) = 7600 - 70 × 100

I.e (80 b - 70 b) + (70 g - 70 g) = 7600 - 7000

Or, 10 b + 0 = 600

∴  b = \dfrac{600}{10}

i.e b = 60

So, The number of boys participated in quiz = b = 60

Put the value of b into eq A

∵ b + g = 100

So, g = 100 - b

Or, g = 100 - 60

i.e g = 40

So, The number of girls participated in quiz = g = 40

Hence, The number of girls participated in quiz is 40 . Answer

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