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sveticcg [70]
3 years ago
12

Three of four numbers have a sum of 22. If the average of the four numbers is 8, what is the fourth number?

Mathematics
1 answer:
Delvig [45]3 years ago
6 0
Let x_1,\ldots,x_4 be the four numbers. Their average is 8, so

\dfrac{x_1+x_2+x_3+x_4}4=8

You know that three of the numbers have a sum of 22, so

\dfrac{22+x_4}4=8

Solve for x_4:

\dfrac{22+x_4}4=8\implies22+x_4=32\implies x_4=10
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Write a function in any form that would match the graph shown below
ella [17]

Answers:

  • Vertex form:  y = -2(x-1)^2 + 8
  • Standard form: y = -2x^2 + 4x + 6

Pick whichever form you prefer.

=============================================================

Explanation:

The vertex is the highest point in this case, which is located at (1,8).

In general, the vertex is (h,k). So we have h = 1 and k = 8.

One root of this parabola is (-1,0). So we'll plug x = -1 and y = 0 in as well. As an alternative, you can go for (x,y) = (3,0) instead.

Plug those four values mentioned into the equation below. Solve for 'a'.

y = a(x-h)^2 + k

0 = a(-1-1)^2+8

0 = a(-2)^2+8

0 = 4a+8

4a+8 = 0

4a = -8

a = -8/4

a = -2

The vertex form of this parabola is   y = -2(x-1)^2+8

Expanding that out gets us the following

y = -2(x-1)^2+8

y = -2(x^2-2x+1)+8

y = -2x^2+4x-2+8

y = -2x^2+4x+6 .... equation in standard form

7 0
2 years ago
Simplest form of 4500:80000 and 8100:144000​
a_sh-v [17]

9514 1404 393

Answer:

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  • 9/160

Step-by-step explanation:

Divide each number in the ratio by their greatest common divisor.

  4500 : 80000 = (4500/500) : (80000/500) = 9 : 160

  8100 : 144000 = (8100/900) : (144000/900) = 9 : 160

3 0
3 years ago
For f(x) = 3x+1 and g(x) = x^2-6, find (g/f)(x)
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G/f(x) = x^2 - 6 / 3x + 1
3x + 1 = x^2 - 6
x^2 - 3x - 6 - 1 = 0
x^2 - 3x - 7 = 0
x = 4.54 , x = - 1.54

i am a mathematics teacher. if anything to ask please pm me
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3 years ago
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lisov135 [29]
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