Answer:

model: 
profit in year 2017: 
Step-by-step explanation:
The sales increased from 2 billion dollars to 146 billion dollars in five years, so to find the increase in billion dollars per year, we just need to divide the increase by the amount of time:

To construct a model for these sales, we can use the year 2003 as the initial point of a linear equation:

the variable y will represent the profit in billion dollars, the variable x will represent our time, so we can use (t - 2003) in its place to represent the number of years since 2003 (t is the year we want to calculate), the constant 'a' will be our rate of 28.8, and the constant 'b' is the inicial value for the year 2003, that is, 2 (billions). So we have:

In the year 2017, we would have:



Answer:
100 ≥ 12x + 28
Step-by-step explanation:
He needs $100 for the new bike but already has the $28 so you also have to add 12x because thats what you need to find. X represents the amount of days he has to work.
First, factor out 5:
5 (x² -x -20)
We need two numbers that add to -1 and multiply to -20. -5 and 4 satisfy this.
5(x-5)(x+4)
Lol i dont know the answer but i love your profile pic again sorry
Given that average mass of an ant
grams.
Given that average mass of a giraffe
Kilograms.
Now we have to find about how many times more mass does a giraffe have than an ant. Before carring out any comparision, we must make both units equal.
Like convert kilogram into gram or gram into kilogram.
I'm going to convert kilogram into gram using formula
1 Kg = 1000 g
So the average mass of a giraffe
grams.
Now we just need to divide mass of giraffe by mass of ant to find the answer.





=666666666.667
Hence final answer is
which is approx 666666666.667.