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kolbaska11 [484]
3 years ago
13

If you need carpet that is 6 1/2 long and 5 3/4 wide how many square feet do you need for the carpet??

Mathematics
1 answer:
Orlov [11]3 years ago
6 0

Find the area

A= l*w

A = (6 1/2) * (5 3/4)

6 1/2 =  (2*6+1)/2 =13/2

5 3/4 = (4*5+3)/4 = 23/4

A = 13/2 * 23/4

299/8

37 3/8

37 3/8 ft^2

Answer: 37  3/8 ft^2

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f(t)=h=-16t^2+20t+6



a=-16, b=20, c =6

Δ=b^2-4ac=20^2-4*(-16)*6=400+384=784

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max:

p=-\frac{b}{2a}=-\frac{20}{-32}=\frac{20}{32}=\frac{5}{8}

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h=-\frac{25}{4}+\frac{50}{4}+6=\frac{-25+50+24}{4}=\frac{49}{4}

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t=\frac{-20-28}{-32}=\frac{-48}{-32}=\frac{3}{2}=1.5

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3 years ago
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Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

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Take the inverse tangent of both sides:

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or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

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3 years ago
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