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Viktor [21]
3 years ago
8

Solving InequalitiesAlgebra 1​

Mathematics
2 answers:
Stells [14]3 years ago
7 0

Answer:

<u>p</u>\leq<u>8</u>

Step-by-step explanation:

Step 1- Add 7 to both sides of the inequality.

New inequality:

\frac{p}{8} \leq1

Step 2- Now multiply by 8 on both sides of the inequality to get your answer.

Answer:

p\leq8

Law Incorporation [45]3 years ago
4 0

Answer:

p \leq \\ 8

Step-by-step explanation:

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A pharmaceutical company receives large shipments of ibuprofen tablets and uses an acceptance sampling plan. This plan randomly
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Answer:

0.7208 = 72.08% probability that this whole shipment will be accepted.

Step-by-step explanation:

For each tablet, there are only two possible outcomes. Either it meets the required specifications, or it does not. The probability of a tablet meeting the required specifications is independent of any other tablet, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

4% rate of defects

This means that p = 0.04

26 tablets

This means that n = 26

What is the probability that this whole shipment will be accepted?

Probability that at most one tablet does not meet the specifications, which is:

P(X \leq 1) = P(X = 0) + P(X = 1)

Thus

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{26,0}.(0.04)^{0}.(0.96)^{26} = 0.3460

P(X = 1) = C_{26,1}.(0.04)^{1}.(0.96)^{25} = 0.3748

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.3460 + 0.3748 = 0.7208

0.7208 = 72.08% probability that this whole shipment will be accepted.

3 0
3 years ago
The left and right page numbers of an open book are two consecutive integers whose sum is 321
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Answer:

160,160

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pages 160 161

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