Answer:
The cell reaction reaches equilibrium quickly and the cell emf becomes zero.
Explanation:
The purpose of a salt bridge is not to move electrons from the electrolyte, its main function is to maintain charge balance because the electrons are moving from one-half cell to the other.
A solution of a salt that dissociates easily is normally used. Water is ineffective at functioning as a salt bridge. Hence the effect stated in the answer.
Answer:
1) combustion
2) double replacement
3) combination
4) combustion
Explanation:
The combustion of a compound refers to the reaction of that compound with oxygen to produce heat and light. In reactions (1) and (4) above, ethanol and methane reacted with oxygen to yield carbon dioxde and water. This is a combustion reaction.
Reaction(2) is a double replacement reaction because the both cations exchange their anion partners in the product.
Reaction (3) is a combination reaction. It involves the joining of two elements to form a new compound.
Answer : The percentage aniline protonated is, 0.0209 %
Explanation :
First we have to calculate the pOH.
Now we have to calculate the hydroxide ion concentration.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![5.68=-\log [OH^-]](https://tex.z-dn.net/?f=5.68%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=2.09\times 10^{-6}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D2.09%5Ctimes%2010%5E%7B-6%7DM)
The equilibrium chemical reaction will be:
From the reaction we conclude that,
Concentration of 
ion = Concentration of 
ion = 
Now we have to calculate the percentage aniline protonated.
Thus, the percentage aniline protonated is, 0.0209 %
For electricity to flow there must be a flow of electrons or ions present in a system or medium. When electricity is passed in pure water, oxygen does not have d-orbitals or f-orbitals through which electrons may pass. In pure water there are no electrolytic substance, so no ions present in the pure water. Therefore electricity can not pass through pure water. Additionally; water cannot dissociate into OH- and H+ when electricity is passed through pure water.
