The last statement is correct...
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A 250 ml sample of saturated a g o h solution was titrated with h c l , and the endpoint was reached after 2. 60 ml of 0. 0136 m h c l was dispensed. Based on this titration, what is the k s p of a g o h <u>. Ksp=1.9×10⁻⁸</u>
<h3>What is titration?</h3>
Titration is a typical laboratory technique for quantitative chemical analysis used to calculate the concentration of a specified analyte. It is also referred to as titrimetry and volumetric analysis (a substance to be analyzed). A standard solution with a known concentration and volume is prepared as the reagent, also known as the titrant or titrator. To ascertain the concentration of the analyte, the titrant reacts with an analyte solution (also known as the titrand). The titration volume is the amount of titrant that interacted with the analyte.
A typical titration starts with a beaker or Erlenmeyer flask being placed below a calibrated burette or chemical pipetting syringe that contains the titrant and a little amount of the indicator (such as phenolphthalein).
To learn more about titration from the given link:
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Answer:- 1.62 moles
Solution:- At constant temperature and pressure, volume is directly proportional to the moles of the gas.
from given data, 
= 5.17 L, 
= 1.05 moles
= 8.00 L, 
= ?
Let's plug in the values in the formula:
On cross multiply:
= 1.62 moles
So, now the toy contains 1.62 moles of the air.
Answer:
Al(NO3)3(s)--------> Al^3+(aq) + 3NO3^-(aq)
Explanation:
The equation shown above describes the dissolution of Al(NO3)3 in water using the lowest coefficients.
This occurs when solid Al(NO3)3 is added to water. It dissolves to give rise to ions as shown. This is a property of all ionic substances.
Answer: Correct name will be is aluminum bromide
Explanation:
In a molecular formula ,
Aluminium atoms present = 1
Bromine atoms present = 3
Charge on aluminium is +3 and charge on bromine is -1.
While naming:
- Name of the cation is written first. Simple name of the element is written
- After name of cation name of an anions written with suffix 'ide' in the end.
So, the name of will be aluminium bromide.
