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3 years ago

The research method.l That is also referred to as fieldwork is

Chemistry

2 answers:

Phoenix [80]3 years ago

8 0

Answer: Option (D) is the correct answer.

Explanation:

Fieldwork is defined as the process of collecting information from the environment or to do practical work.

Field work requires active participation of the participant so that correct information can be collected to complete their records.

Thus, we can conclude that the research method. That is also referred to as fieldwork is participant observation.

WITCHER [35]3 years ago

6 0

The answer to your question is "Participant Observation".

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Draw structures from the following names, and determine which compounds are optically active:(c) 1,2-dibromo-2-methylbutane

dolphi86 [110]

The given compound 1,2-dibromo-2-methylbutane is an optically active compound .

Because this compound does not have plane of symmetry (POS) and center of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .

It has chiral center.

Here , the chiral carbon is attached to the 4 distinct groups such as : methyl , ethyl , bromine , bromomethane .

<h3>What is di-symmetry?</h3>

Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .

<h3>Chiral center :</h3>

Have Sp3 hybridized center (4sigma bond ) .

4 distinct group is attached to the chiral atom. form non -superimposable mirror image .

<h3>What is optical isomerism ?</h3>

Same molecular formula and same structural formula . also have same physical and chemical properties .

They differ in their behavior towards plane polarized light (ppl) .

Learn more about chiral center here:

brainly.com/question/9522537

#SPJ4

8 0

2 years ago

Will a precipitate of magnesium fluoride form when 300. mL of 1.1 × 10 –3 M MgCl 2 are added to 500. mL of 1.2 × 10 –3 M NaF? [K

Tju [1.3M]

Answer:

No precipitate is formed.

Explanation:

Hello,

In this case, given the dissociation reaction of magnesium fluoride:

$MgF_2(s)\rightleftharpoons Mg^{2+}+2F^-$

And the undergoing chemical reaction:

$MgCl_2+2NaF\rightarrow MgF_2+2NaCl$

We need to compute the yielded moles of magnesium fluoride, but first we need to identify the limiting reactant for which we compute the available moles of magnesium chloride:

$n_{MgCl_2}=0.3L*1.1x10^{-3}mol/L=3.3x10^{-4}molMgCl_2$

Next, the moles of magnesium chloride consumed by the sodium fluoride:

$n_{MgCl_2}^{consumed}=0.5L*1.2x10^{-3}molNaF/L*\frac{1molCaCl_2}{2molNaF} =3x10^{-4}molMgCl_2$

Thus, less moles are consumed by the NaF, for which the moles of formed magnesium fluoride are:

$n_{MgF_2}=3x10^{-4}molMgCl_2*\frac{1molMgF_2}{1molMgCl_2}=3x10^{-4}molMgF_2$

Next, since the magnesium fluoride to magnesium and fluoride ions is in a 1:1 and 1:2 molar ratio, the concentrations of such ions are:

$[Mg^{2+}]=\frac{3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =3.75x10^{-4}M$

$[F^-]=\frac{2*3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =7.5x10^{-4}M$

Thereby, the reaction quotient is:

$Q=(3.75x10^{-4})(7.5x10^{-4})^2=2.11x10^{-10}$

In such a way, since Q<Ksp we say that the ions tend to be formed, so no precipitate is formed.

Regards.

6 0

3 years ago

The Kelvin scale is based on the concept of absolute zero.explain the concept

allsm [11]

Answer:Absolute zero is the lowest possible temperature where nothing could be colder and no heat energy remains in a substance. ... By international agreement, absolute zero is defined as precisely; 0 K on the Kelvin scale, which is a thermodynamic (absolute) temperature scale; and –273.15 degrees Celsius on the Celsius scale.

Explanation:

6 0

3 years ago

Which of the following examples of erosion would occur most quickly?

anyanavicka [17]

Answer: OC

Explanation:

The Others Could Take Many Millions Of Years

8 0

3 years ago

Can anyone please help me find molar masses of compounds. For example Copper (ll) sulfate (CuSO4)

Alina [70]

Answer:

Explanation:

You would have to add up the atomic masses of all the compounds in the compound, making sure you include how many molecules of each are in the compound

For example, in CuSOA we have 1 molecule of Cu and S, as 4 molecules of O

The atomic masses are as follows:

Cu = 63.55 u

S = 32.065 u

O = 15.99 units

This is how we would add it up:

(Atomic mass of Cu) + (Atomic mass of S) + 4(Atomic Mass of O)

(63.55) + (32.065) + 4(15.99)

(63.55) + (32.065) + 63.96

= 159.575 u

7 0

2 years ago

Read 2 more answers