Given:
Trapezoid with bases 10 and 20, and height of the trapezoid is 6.
To find:
The area of the trapezoid.
Solution:
We know that the area of a trapezoid is:

Where, h is the height of the trapezoid and
are bases of the trapezoid.
Putting
in the above formula, we get



The area of the trapezoid is 90 sq units. Therefore, the correct option is A.
Answer:
B. The graph has no zeros.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that evolution theory hypothesizes that people should spontaneously follow a 24-hour cycle of sleeping and wakingdash–even if they are not exposed to the usual pattern of sunlight.
Sample size n = 8
df = 8- 1=7
Since population std deviation is not known, and sample size is small we can use only t test

(two tailed test at 5% level of significance)
24
28
24
22
25
26
26
25
mean 25
sd 3.142857143
se 1.111167799
Test statistic = Mean diff/se = 1.595
p = 0.1546
since p >0.05, accept null hypothesis.
There is no evidence to prove that the steady cycle is different from 24 hours.
Answer:

Step-by-step explanation:
Given
See attachment
Required
Determine the measure of 
.
So, we have:

Where:


Substitute these values in the above equation.


Collect Like Terms:


Answer:
(3,2)
Step-by-step explanation:
The system is
x + y = 5
x -y = 1
Add the equations to eliminate y
2x = 6----->x=3
Substitute this value in any equation
3+y = 5----->y=2
The solution is (3,2)