Question

a student buys a rope at the store the label on the packaging says that the Rope is 2.15 m in length the student measures the robe as 1.85 M what is the students percent error?

Answer 1

Answer: The percentage error of the student is 13.95 %.

Explanation:

To calculate the percentage error, we use the equation:

$\%\text{ error}=\frac{|\text{Experimental value - Accepted value}|}{\text{Accepted value}}\times 100$

We are given:

Length of rope measured by student = 1.85 m

Actual length of the rope = 2.15 m

Putting values in above equation, we get:

$\%\text{ error}=\frac{|1.85-2.15|}{2.15}\times 100\\\\\%\text{ error}=13.95\%$

Hence, the percentage error of the student is 13.95 %.

Answer 2

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