Which term refers to compounds with the same molecular formula but different structural formulas?

Balance each reaction and write its reaction quotient, Qc:(b) POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Komok [63]

When we balance the given equation

POCl₃(g) ⇄ PCl₃(g) + O₂(g)

We will get

2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

Solution:

Balancing the given equation

POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Balancing the number of O

2POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Balancing the number of P and Cl

2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

We get the balanced equation

2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

The reaction quotient will be

Qc = [product] / [reactant]

Qc = [PCl₃(g) + O₂(g)] / [POCl₃(g) ]

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4 0

2 years ago

The graph below shows how solubility changes with temperature.

Otrada [13]

The two solutions that have similar solubilities at 40°C will be Na₂HAsO₄ and Na₂SO₄.

<h3>What is solubity ?</h3>

It is the ability of a solute to be dissolved, especially in water.

As the temperature increases the solubility of the gas generally decreases"

According to given information and graph attached as reference ;

Solubility of NaCl (sodium chloride) at 40°C is 36.3 grams.
Solubility of Na₂SO₄ (sodium sulfate) at 40°C is 48.8 grams.
Solubility of Na₂HAsO₄ (sodium arsenate dibasic) at 40°C is 48.9
grams.
Solubility of Ba(NO₃)₂ (barium nitrate) at 40°C is 14.1 grams.
Solubility of Ce₂(SO₄)₃·9H₂O (ceasium sulfate nonahydrate) at 40°C is 6.2 grams.

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4 0

2 years ago

Why doesn't it matter which nonradioactive isotope of oxygen you breathe?

Greeley [361]

Isotopes of an element have same atomic number (number of protons) but vary in the mass number (number of neutrons). The chemical reactivity of an element is not affected by the change in mass number. So, for stable isotopes of Oxygen, (Oxygen-16, Oxygen-17 and Oxygen-18) the biochemical pathway of oxygen breathed in during respiration remains unaffected even with different isotopes. Only the radioactive isotopes of oxygen when breathed in may cause serious health hazards as they emit radiations that may damage the internal organs in the body.

4 0

4 years ago

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A chemist prepares a solution of vanadium chloride by measuring out of into a volumetric flask and filling to the mark with dist

user100 [1]

The question is incomplete, the complete question is:

A chemist prepares a solution of vanadium (III) chloride (VCl3) by measuring out 0.40g of VCl3 into a 50.mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of Cl− anions in the chemist's solution. Be sure your answer is rounded to the correct number of significant digits.

Answer:

0.153M of anions

Explanation:

First we calculate the concentration of the solution. From m/M= CV

m=given mass, M= molar mass, C =concentration of solution, V= volume of solution

Molar mass of compound= 51 + 3(35.5)= 157.5gmol-1

0.4g/157.5gmol-1= C×50/1000

C= 2.54×10-3/0.05= 0.051M

But 1 mole of VCl3 contains 3 moles of anions

Therefore, 0.051M will contain 3×0.051M of anions= 0.153M of anions

4 0

3 years ago

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Imagine a drop of water in oil. If you add surfactant, explain how the surfactant molecules organize themselves around the water

Oduvanchick [21]

If you add a surfactant in water-oil mixture, surfactant molecules would form micelles wherein the hydrophobic end of the surfactant faces inside the micelle while the hydrophilic end faces the water molecules. Inside these micelles oil particles are attached.

4 0

4 years ago