Answer:
the % yield is 82%
Explanation:
Given the data in the question,
we know that;
Molar mass of benzil is 210.23 g·mol−1
Molar mass of dibenzyl ketone is 210.27 g·mol−1
Molar mass of tetraphenylcyclopentadienone is 384.5 g·mol−1
Now,
2.0 g benzil = 2 g / 210.23 g·mol−1 = 0.0095 mole
2.2 g dibenzyl ketone = 2.2 / 210.27 = 0.0105 mole
3.0 g of tetraphenylcyclopentadienone = 3 / 384.5 = 0.0078 mole
Now, the limiting reagent is benzil. 0.0095 mole can reacts wiyh 0.0095 mole of dibenzyl ketone
percentage yield = ( 0.0078 mole / 0.0095 mole ) × 100%
= 0.82 × 100%
= 82%
Therefore, the % yield is 82%
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Answer:
Keq = [NO₂]²/[N₂O₄] = 0.2.
Explanation:
- For the gas mixture equilibrium:
<em>N₂O₄ ⇄ 2NO₂</em>
The expression of the equilibrium constant (Keq):
Keq = [NO₂]²/[N₂O₄]
<em>∴ Keq = [NO₂]²/[N₂O₄]</em> = (0.03)²/(0.0045) = <em>0.2.</em>
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