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3 years ago

State a point ...please help me

Mathematics

1 answer:

dlinn [17]3 years ago

4 0

Answer:

the blue rotates -270 degrees

Step-by-step explanation:

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Write a problem involving how much more Than and solve it. Explain how drawing a diagram helped you solve the problem

avanturin [10]

A very simple example problem to satisfy the required above is,
"John has 8 apples and 17 oranges. How much more oranges does John has than apple?"

To answer this item, one needs to subtract the number of apples from the number of oranges. This is as shown below,
D = 17 - 8 = 9

The concept of "how much more than" is linked to finding the difference between the numbers.

6 0

3 years ago

a bakery sold 31 bagels in the first hour of business and 42 bagels in the second hour. if the baker had 246 bagels to start, ho

bogdanovich [222]

Answer:

173 bagels were left after the second hour!!

Step-by-step explanation:

7 0

2 years ago

Use distributive property to simplify 5 ( 6x - 2 )

uysha [10]

The answer would be 30x-10

6 0

3 years ago

Read 2 more answers

If fg = 2 units, fi = 7 units, and hi = 1 unit , what is gh

Vikentia [17]

See the picture to better understand the problem

F________G_______H_______I

we know that
FI=FG+GH+HI-----> solve for GH
GH=FI-FG-HI
FI=7 units
FG=2 units
HI=1 unit
substitute
GH=7-2-1-----> GH=4 units

the answer is
GH=4 units

5 0

3 years ago

An urn contains 8 red chips, 10 green chips, and 2 white chips. A chip is drawn and replaced, and then a second chip is drawn.

Harlamova29_29 [7]

Answer:

(A) 0.04

(B) 0.25

Step-by-step explanation:

Let R = drawing a red chips, G = drawing green chips and W = drawing white chips.

Given:

R = 8, G = 10 and W = 2.

Total number of chips = 8 + 10 + 2 = 20

$P(R) = \frac{8}{20}=\frac{2}{5}\\P(G)= \frac{10}{20}=\frac{1}{2}\\P(W)= \frac{2}{20}=\frac{1}{10}$

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.

(A)

Compute the probability of selecting a white chip on the first and a red on the second as follows:

$P(1^{st}\ white\ chip, 2^{nd}\ red\ chip)=P(W)\times P(R)\\=\frac{1}{10}\times \frac{2}{5}\\ =\frac{1}{25} \\=0.04$

Thus, the probability of selecting a white chip on the first and a red on the second is 0.04.

(B)

Compute the probability of selecting 2 green chips:

$P(2\ Green\ chips)=P(G)\times P(G)\\=\frac{1}{2} \times\frac{1}{2}\\ =\frac{1}{4}\\ =0.25$

Thus, the probability of selecting 2 green chips is 0.25.

(C)

Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

$P(2^{nd}\ red\ chip|1^{st}\ white\ chip)=\frac{P(2^{nd}\ red\ chip\ \cap 1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\=\frac{P(2^{nd}\ red\ chip)P(1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\= P(R)\\=\frac{2}{5}\\=0.40$

Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.

6 0

2 years ago