Answer:
6) x=9.75
10) Triangle OMN ~ Triangle ODK; SSS ~
11) SSS ~ theorem
12) SSS ~ theorem
Step-by-step explanation:
For #6, since the polygons are similar, then it must mean AD is congruent to JM and CD is congruent to LM. Now we can set up the proportion 39/20=x/5 and solve. Solving for x gets us x=9.75, so C is the correct choice
For #10, there's no information about angles whatsoever in the diagram, so B and C must be wrong. D must be wrong as well because if the triangles weren't similar, then why is OJ ~ JM and OK ~ KN? So thus, the triangles are similar by SSS.
For #11, this is sort of a no-brainer because there's no mention of angles, so D must be correct.
For #12, same concept, no mention of angles, all sides are similar to their respective sides of the different triangles, so A is correct.
Answer:
(3.5, -4.5) or option D
Step-by-step explanation:
x) (6 + 1) / 2 = 3.5
y) (-1 + (-8)) / 2 = -4.5
The answer to this question is true. If i'am right this from k12 and edg-enuity. have a good day bro. ;)
Answer:
x = (-27)/11
Step-by-step explanation:
Solve for x:
(-11 x)/54 - 1/2 = 0
Put each term in (-11 x)/54 - 1/2 over the common denominator 54: (-11 x)/54 - 1/2 = (-27)/54 - (11 x)/54:
(-27)/54 - (11 x)/54 = 0
(-27)/54 - (11 x)/54 = (-11 x - 27)/54:
(-11 x - 27)/54 = 0
Multiply both sides of (-11 x - 27)/54 = 0 by 54:
(54 (-11 x - 27))/54 = 54×0
(54 (-11 x - 27))/54 = 54/54×(-11 x - 27) = -11 x - 27:
-11 x - 27 = 54×0
0×54 = 0:
-11 x - 27 = 0
Add 27 to both sides:
(27 - 27) - 11 x = 27
27 - 27 = 0:
-11 x = 27
Divide both sides of -11 x = 27 by -11:
(-11 x)/(-11) = 27/(-11)
(-11)/(-11) = 1:
x = 27/(-11)
Multiply numerator and denominator of 27/(-11) by -1:
Answer:x = (-27)/11
Answer:
8.284 × 10^4 m^2
Step-by-step explanation:
The area is the product of length and width:
(5.45·10^5 m)·(0.152 m) = 0.8284·10^5 m^2 = 8.284·10^4 m^2
