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3 years ago

Line perpendicular to the line that goes through (0,0) and (3,2)

1 answer:

7 0

Since the first line passes thru the origin, you can read off its slope from the coordinates of the other point (3,2): the slope is m = 2/3.

A line perpendicular to the first has slope -3/2, the negative reciprocal of 2/3.

Thus, the perpendicular line is y = (-3/2)x + b. Subbing 0 for y and 0 for x, we get b = 0. Therefore, the equation of this new line is y = (-3/2)x.

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The factorization of 8x3 -125 is (2x-5)(jx2 +kx+25)

lbvjy [14]

$\bf ~\hspace{10em}\textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 8x^3-125~~ \begin{cases} 8=2\cdot 2\cdot 2\\ \qquad 2^3\\ 125=5\cdot 5\cdot 5\\ \qquad 5^3 \end{cases}\implies 2^3x^3-5^3\implies (2x)^3-5^3 \\[2em] [2x-5][(2x)^2+(2x)(5)+5^2]\implies (2x-5)(\stackrel{\stackrel{j}{\downarrow }}{4}x^2+\stackrel{\stackrel{k}{\downarrow }}{10}x+25)$

3 0

3 years ago

What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

5 0

3 years ago

Read 2 more answers

What is the first step in solving the equation?<br> +4= -2

adell [148]

Answer:

adding +2 on both sides to remove the -2 then it would be 2=0

Step-by-step explanation:

8 0

2 years ago

Given the function f(x) = 3|x – 2| + 6, for what values of x is f(x) = 18?

Gwar [14]

Answer:

x = - 2, x = 6

Step-by-step explanation:

Given f(x) = 18 we require to solve

3 | x - 2 | + 6 = 18 ( subtract 6 from both sides )

3 | x - 2 | = 12 ( divide both sides by 3 )

| x - 2 | = 4

The absolute value function always returns a positive value, however, the expression inside can be positive or negative, thus

x - 2 = 4 ( add 2 to both sides )

x = 6

- (x - 2) = 4

- x + 2 = 4 ( subtract 2 from both sides )

- x = 2 ( multiply both sides by - 1 )

x = - 2

As a check substitute these values into the left side of the equation and if equal to the right side then they are the solutions

x = 6 → 3|6 - 2| + 6 = 3|4| + 6 = 3(4) + 6 = 12 + 6 = 18 ← True

x = - 2 → 3|- 2 - 2| + 6 = 3|-4| + 6 = 3(4) + 6 = 12 + 6 = 18 ← True

Hence solutions are x = - 2, x = 6

7 0

2 years ago

Read 2 more answers

18x (14 - 9) ÷[12 - (19 - 13)] = what is the answer

marysya [2.9K]

Answer:

Step-by-step explanation:

18 . ( 14 - 9 ) ÷ [ 12 - ( 19 - 13 ) ]

18 . ( 5 ) ÷ [ 12 - 6 ]

90 ÷ 6

5 0

2 years ago