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anyanavicka [17]
3 years ago
7

Please help! Will mark brainlist!

Mathematics
2 answers:
Anna007 [38]3 years ago
7 0

Answer:

C

Step-by-step explanation:

We need to find the area of BOTH the rectangle AND the triangle. So the formula to find area of a triangle is bh\frac{1}{2\\}, or bh/2

b- base

h height

And obviously to find area of rectangles and stuff like that is just l x w

So let's find area of the rectangle, AKA the whole,

5x11=55

The area of the rectangle is 55

Now for the triangle,

The base is 5, and the height is 3. 5 x 3 = 15, and 15/2 = 7.5

The area of the triangle is 7.5

Now, subtract because we don't want the area of the triangle BUT the shaded region, so 55-7.5= 47.5 We have to add a unit so its 47.5^2, so the answer is C

Hope this helps!!

-Ketifa

harina [27]3 years ago
6 0
C

I had to do this question to
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alex41 [277]

Answer:

✔️2 sets of corresponding angles

<D and <S

<R and <L

✔️2 sets of corresponding sides

DR and SL

RM and LT

Step-by-step explanation:

When two polygons are congruent, it implies that they have the same shape and size. Therefore, their corresponding angles and sides are congruent to each other.

When naming congruent polygons, the arrangement of the vertices are kept in a definite order of arrangement.

Therefore, Given that polygon DRMF is congruent to SLTO, the following angles and sides correspond to each other:

<D corresponds to <S

<R corresponds to <L

<M corresponds to <T

<F corresponds to <O

For the sides, we have:

DR corresponds to SL

RM corresponds to LT

MF corresponds to TO

FD corresponds to OS.

We can select any two out of these sets of corresponding angles and sides as our answer. Thus:

✔️2 sets of corresponding angles

<D and <S

<R and <L

✔️2 sets of corresponding sides

DR and SL

RM and LT

4 0
3 years ago
Pls answer enclosed questions :))
Vsevolod [243]
A) 9a+6b
b)5c-3d
combine like terms*
4 0
3 years ago
Read 2 more answers
simplify the expression below. Express the simplified expression in standard form (12s^4-6s^2+4s)+(6s^4-4s+27)-(4s^4+s^2+12)
joja [24]
<h3>Answer:   14s^4 - 7s^2 + 15</h3>

====================================================

Work Shown:

(12s^4-6s^2+4s)+(6s^4-4s+27)-(4s^4+s^2+12)

12s^4-6s^2+4s+6s^4-4s+27-4s^4-s^2-12

(12s^4+6s^4-4s^4)+(-6s^2-s^2)+(4s-4s)+(27-12)

14s^4-7s^2+0s+15

14s^4-7s^2+15

Note: don't forget to distribute the negative to every term in the last parenthesis

3 0
3 years ago
Compare 9 × (11 – 4) and 3 × (11 – 4). A. 9 × (11 – 4) is three times as much as 3 × (11 – 4). B. 9 × (11 – 4) is nine times as
liubo4ka [24]

Hello there!

So there are two separate problems: 9 * (11-4) and 3 * (11-4). To find the value for each expression, use order of operations. We'll solve what's in the parenthesis before multiplying that value by the other number. 11-4 is 7. 7 * 9 is 63. 11-4 is 7. 7 * 3 is 21. You can divide 63 by 21 to get 3. This means that 9 * (11 - 4) is three times as much as 3 *(11 - 4). Even just by looking at the problem, the expression in the parenthesis is the same thing, but the front numbers are different. 9 is three times as much as 3.  The answer is A.

3 0
3 years ago
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Can someone walk me through this please?
Snezhnost [94]
Here it is.Hope it helpful
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