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3 years ago

How many tenths are in 15.03

1 answer:

7 0

There are 10 "tenths" in one whole number.

15 --> 15 whole numbers --> 15 * 10 = 150 --> 150 tenths

0.03 --> 3 hundredths --> 10 hundredths = 1 tenth --> 3/10 tenth

150 3/10 tenths in 15.03

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In the Accompanying diagram of circle O, chords AB and CD intersect at E, mAC=50 and mBD =150. Find m

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Step-by-step explanation:

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3 years ago

Simplify the following expression. 3 2/5x3(-7/5)

Studentka2010 [4]

The simplified expression of 32/5 x 3(-7/5) is -672/25

<h3>How to simplify the expression?</h3>

The mathematical expression is given as:

32/5 x 3(-7/5)

Evaluate the product of 3 and -7/5

32/5 x 3(-7/5) = 32/5 x -21/5

Evaluate the product of 32 and -21

32/5 x 3(-7/5) = 672/5 x -1/5

Evaluate the product of 5 and 5

32/5 x 3(-7/5) = 672/25 x -1

So, we have:

32/5 x 3(-7/5) = -672/25

Hence, the simplified expression of 32/5 x 3(-7/5) is -672/25

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brainly.com/question/723406

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2 years ago

Justin has $500 in a savings account at the beginning of the summer. He wants to have at least $300 in the account by the end of

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Answer:

10 weeks

Step-by-step explanation:

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2 years ago

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the answer is 1,050 ft2

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2 years ago

A student answers a multiple-choice examination question that offers four possible answers. Suppose the probability that the stu

Salsk061 [2.6K]

Answer:

The value is $P(A | W) = 0.941$

Step-by-step explanation:

From the question we are told that

The probability that the student knows the answer to the question is $P(A) = 0.8$

The probability that that the student will guess is $P(G) = 0.2$

The probability that that the student get the correct answer given that the student guessed is $P(W /G) = 0.25$

Here W denotes that the student gets the correct answer

Generally it a certain fact that if the student knows the answer he would get it correctly

So the probability the the student got answer given that he knows it is

$P(W | A) = 1$

Generally from Bayes theorem we can mathematically evaluate the probability that the student knows the answer given that he got it correctly as follows

$P(A | W) = \frac{ P(A) * P(W | A )}{ P(A) * P(W | A) + P(G) * P(W| G)}$

=> $P(A | W) = \frac{ 0.8 * 1}{ 0.8 * 1+ 0.2 * 0.25}$

=> $P(A | W) = 0.941$

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3 years ago