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zzz [600]
4 years ago
10

How many tenths are in 15.03

Mathematics
1 answer:
Brilliant_brown [7]4 years ago
7 0
There are 10 "tenths" in one whole number.

15 --> 15 whole numbers --> 15 * 10 = 150 --> 150 tenths

0.03 --> 3 hundredths --> 10 hundredths = 1 tenth --> 3/10 tenth

150 3/10 tenths in 15.03
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Du/dr=(1+sqrt(r))/(1+sqrt(u))_
Maslowich
Solution is supposed to be as follows
<span>u+<span>2 / 3</span><span> u<span>^3/2</span></span>
=r+<span>2 / 3</span><span> r^<span>3/2</span></span> + <span>c</span></span>
4 0
3 years ago
A video game has the following formula: For every 1,333 in attack power, you gain 3 levels. You get one bonus star per every 38
aleksley [76]

Answer:

Rounded to a whole number, the player has 12 bonus stars.

Step-by-step explanation:

Since the video game establishes that for every 1,333 points of attack power 3 levels are gained, and that the player has a total of 0.21 million attack points, to determine the number of levels that player has it is necessary to perform the following calculation :

0.21 million = 210,000

210,000 / 1,333 x 3 = Levels

472.6 = Levels

Now, every 38 levels, the game awards a bonus star. To determine the amount of bonus stars that the player has, the following division must be made:

472.6 / 38 = X

12.43 = X

Thus, rounded to a whole number, the player has 12 bonus stars.

7 0
3 years ago
Which expression is equivalent to 10x2 - (2 – 3x) + (5x - 3x2)?​
djverab [1.8K]
10x^2 - (2 - 3x) + (5x - 3x^2)
=7x^ + 2x - 2
5 0
3 years ago
Read 2 more answers
What is the area of the triangle? 5 4 3 units?​
tankabanditka [31]

Answer:

6 units squared

Step-by-step explanation:

Formula:

area = 0.25 * √( (a + b + c) * (-a + b + c) * (a - b + c) * (a + b - c) )

Assign variables:

A = 5, B = 4, C = 3.

Distribute:

area = 0.25 * √( (5 + 4 + 3) * (-5 + 4 + 3) * (5 - 4 + 3) * (5 + 4 - 3) )

Combine like terms

area = 0.25 * √( (12) * (2) * (4) * (6) )

Multiply:

area = 0.25 * √(576)

Square root:

area = 0.25 * 24

Multiply:

area = 6 units squared

4 0
2 years ago
Y=x2-2x-5<br> Change to vertex form
MaRussiya [10]

The vertex form is y=(x-1)^{2} -6

Step-by-step explanation:

The given equation y=x^{2} -2x-5 is a parabola. The vertex of the parabola is of the form y=ax^{2} +bx+c  

The parameters of the parabola are a=1, b=-2 and c=-5

The vertex of the x-coordinate is given by x=\frac{-b}{2a}

Thus, substituting the values of a and b in x=\frac{-b}{2a}, we get,

\begin{aligned}x &=\frac{-(-2)}{2(1)} \\&=\frac{2}{2} \\x &=1\end{aligned}

Now, substituting x=1 in y=x^{2} -2x-5, we get,

\begin{aligned}y &=1^{2}-2(1)-5 \\&=1-2-5 \\y &=-6\end{aligned}

Thus, the vertex is (1,-6)

The equation of parabola to be in vertex form is y=a(x-h)^{2} +k

where a is the coefficient of x^{2}, h is vertex of the x-coordinate and k is the vertex of the y-coordinate.

Hence, a=1, h=1 and k=-6

Thus, substituting the values in the equation of the vertex form,

y=1(x-1)^{2} -6\\y=(x-1)^{2} -6

Hence, the vertex form is y=(x-1)^{2} -6

8 0
4 years ago
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