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stiks02 [169]
4 years ago
7

Find the percent increase in volume when 1 foot is added to each dimension of the prism. Round your answer to the nearest tenth

of a percent. Percent increase ≈ %
Mathematics
1 answer:
Olin [163]4 years ago
4 0

Answer:

The percentage increase in volume of the prism is impossible to find. This is because the current dimension or the diagram from which the dimension of the prism could be determined is not given.

However I will explain the methods to follow in finding this percentage increase, assuming that the current dimension of the prism is given.

Step-by-step explanation:

Assuming the volume the of prism is x ft³. After adding 1 ft to each dimension, the volume becomes y ft³.

The percentage increase = (y/x) × 100

= z%

That is,

Percentage increase = [(New volume) ÷ (Old volume)] × 100

The resulting value, z% is the percentage increase.

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It is believed that the average starting salary for a 21-25 year old college grad exceeds $52,000 per year. Hence, it is desired
gregori [183]

Answer:

The significance level α is 0.02.

Step-by-step explanation:

A hypothesis test for single mean can be performed to determine whether the average starting salary for a 21-25 year old college grad exceeds $52,000 per year.

The hypothesis is defined as follows:

<em>H₀</em>: The average starting salary for a 21-25 year old college grad does not exceeds $52,000 per year, i.e. <em>µ</em> ≤ 52,000.

<em>Hₐ</em>: The average starting salary for a 21-25 year old college grad exceeds $52,000 per year, i.e. <em>µ</em> > 52,000.

The information provided is:

<em>σ</em> = $5,745

<em>n</em> = 65

Also, if \bar X>\$53,460 then the null hypothesis will be rejected.

Here, we need to compute the value of significance level <em>α</em>, the type I error probability.

A type I error occurs when we reject a true null hypothesis (H<em>₀</em>).

That is:

<em>α</em> = P (type I error)

<em>α</em> = P (Rejecting H<em>₀</em>| H<em>₀</em> is true)

   =P(\bar X>53460|\mu \leq 52000)

   =P[\frac{\bar X-\mu_{0}}{\sigma/\sqrt{n}}>\frac{53460-52000}{5745/\sqrt{65}}]

   =P(Z>2.05)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the significance level α is 0.02.

5 0
3 years ago
Find the equivalent expression of 6^-7
Neporo4naja [7]

Answer:

<h2>11</h2>

Step-by-step explanation:

<h2>6+5=11</h2>

and i need more points

3 0
3 years ago
4 = -x - 4; y = 3/2 * x + 4
Tomtit [17]
What do u want to find out
8 0
4 years ago
WILL MARK B!<br> Please I need help I have a quiz
MArishka [77]

Answer:

a) 2x² - x + 3 = x(2x + 1) - 2x

<=> 2x² - x + 3 = 2x² + x - 2x

<=> 3 - x = - x

<=> 3 = 0

=> no solution

b) x/2 - x/3 - x/4 = 1/12

\frac{6x}{12}  -  \frac{4x}{12}  -  \frac{3x}{12}  =  \frac{1}{12}  \\  \\  \frac{ - x}{12}  =  \frac{1}{12}  \\  \\  =  >  - x = 1 \\  \\  \\  <  =  > x = 1

=> the euqation has the solution x = 1

c) |x - 5| = 2|x|

=> x - 5 = 2x

or x - 5 = -2x

<=> x = -5

or 3x = 5

<=> x = -5

x = -5or x = 5/3

d) defined conditions: 2 - x 》 0

<=> x 《 2

we have:

\sqrt{x + 4}  = 2 - x \\  <  =  > x + 4 = (2 - x) {}^{2}   \\  <  =  > x + 4 =  {x}^{2}  - 4x + 4 \\  <  =  >  {x}^{2}  - 5x = 0 \\  <  =  > x(x - 5) = 0 \\

<=> x = 0 (because x 《 2)

e)

\sqrt{5}  =  \frac{1}{25 {}^{x} }  \\   =  > 5 =  \frac{1}{25 {}^{2x} }  \\  <  =  > 5.25 {}^{2x}  = 1  \\ <  =  >  5.5 {}^{4x}  = 1 \\  <  =  > 5 {}^{4x + 1}  = 1 \\  =  > 4x + 1 = 0

<=> x = -1/4

3 0
3 years ago
Read 2 more answers
What is the answer to this question ​
Gre4nikov [31]
4x^2 -2x +3
mark me as brainliest if i’m right !
5 0
3 years ago
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