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lubasha [3.4K]
3 years ago
6

Mileage tests are conducted for a particular model of automobile. If a 98% confidence interval with a margin of error of 1 mile

per gallon is desired, how many automobiles should be used in the test? Assume that preliminary mileage tests indicate the standard deviation is 2.6 miles per gallon.
Mathematics
1 answer:
kipiarov [429]3 years ago
4 0

Answer: 37

Step-by-step explanation:

As per given description in the question, we have

Population standard deviation : \sigma=2.6\text{ miles per gallon}

Critical value for 98% confidence interval = z_{\alpha/2}=2.33

Margin of error : E= 1 mile per gallon

Formula we use to find the sample size :

n=(\dfrac{z_{\alpha/2}\cdot \sigma}{E})^2

i.e. n=(\dfrac{(2.33)\cdot(2.6)}{1})^2

\Rightarrow\ n=36.699364\approx37

Therefore , the number of automobiles should be used in the test =37

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Answer:

-28

Step-by-step explanation:

Let the number be x

Given that,

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8 0
3 years ago
The value of Peter's house has risen 20% a year for the last 3 years. If the value of Peter's home 3 years ago was $110,000.00,
IRISSAK [1]
Increase $110,000 by 20% 3 times.

110,000 x 0.2 = 22000
(0.2 is 20% as a decimal, we needed to convert it to multiply it)

So we must add 22000 to 110,000, then take 20% of the new cost, and repeat.

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Take another 20% of that
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So the value is now $190,080

A much more efficient way to do this would be multiplying 1.2 instead of 0.2, and skipping the adding part, as you already took 100% of it and are adding 20% more.

Hope this helps!
4 0
3 years ago
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For Greta's birthday party, her parents ordered 6 pizzas. If they cut the pizzas into sixths, how many pieces will there be? Cho
saw5 [17]

Options aren't avaible

Answer:

(1 ÷ 1/6) * 6

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Step-by-step explanation:

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Hey there!
The answer is D. 1/5
An explanation is in the attached image below.
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