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Nata [24]
3 years ago
5

How do you separate money?

Mathematics
1 answer:
pochemuha3 years ago
5 0
Well you separate it into different stacks
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Simplify and expand (X+3)(x-3)(3x+3)<br>​
ivolga24 [154]

Answer:

3x^3 + 3x^2 - 27x - 27

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Pls i need help in this
timurjin [86]
It’s a blank screen .. what’s the question ?
7 0
3 years ago
Let f(x)=x^2+5x-36. Enter the x-intercepts of the quadratic function in the boxes.
Kipish [7]

Answer:

X Intercepts: (4,0) and -9,0

Step-by-step explanation:

8 0
2 years ago
The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is
Firlakuza [10]
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.

An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.



Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.

Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.


Part C:
Given that </span><span>Natalie can only attend a school in her designated zone and that Natalie's zone is defined by y < −2x + 2.

To identify the schools that Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.

For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true

For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true

For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false

For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true

For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false

For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
7 0
3 years ago
Simplify: - 4x 5x - 1 + 3-6x 3-6x​
Vitek1552 [10]

Answer:

−45−1+3−63−6

−46−1+3−63−6

−46+2−63−6

Solution:

−46−63−6+2

Step-by-step explanation:

I hope that this is what you are looking for

Have a nice day/night

3 0
3 years ago
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