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VMariaS [17]
4 years ago
9

50 points!!!Adam recorded the number of flower blooms on each of his ten rose bushes. 9, 10, 4, 12, 15, 17, 18, 10, 12, 13If he

combined the number of blooms into one data set, which box plot correctly displays the data?A) B) C) D) what is the median of the data set
Mathematics
2 answers:
Mekhanik [1.2K]4 years ago
7 0

Answer:

Median is 12

Step-by-step explanation:

9, 10, 4, 12, 15, 17, 18, 10, 12, 13

Sort the data

4, 9, 10, 10, 12, 12, 13, 15, 17, 18

Median position: (n+1)/2

(10+1)/2 = 5.5th value

Median:

(12+12)/2

24/2

12

lyudmila [28]4 years ago
6 0

Answer:

12

Step-by-step explanation:

9, 10, 4, 12, 15, 17, 18, 10, 12, 13

Putting the numbers from smallest to largest

4,9, 10, 10, 12  12, 13, 15, 17, 18,

The median is the middle number

There are 10 numbers

4,9, 10, 10, 12          12, 13, 15, 17, 18,

The middle number is between the 12's, so it is 12

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Symmetric property of congruence.

Solution:

Given statement:

If ∠1 ≅ ∠2, then ∠2 ≅ ∠1.

<em>To identify the property used in the above statement:</em>

Let us first know some property of congruence:

Reflexive property:

The geometric figure is congruent to itself.

That is \overline{A B} \cong \overline{A B} \text { or } \angle B \cong \angle B.

Symmetric property of congruence:

If the geometric figure A is congruent to figure B, then figure B is also congruent to figure A.

That is \overline{A B} \cong \overline{C D}, \text { then } \overline{C D} \cong \overline{A B}.

Transitive property of congruence:

If figure A is congruent to figure B and figure B is congruent to figure C, then figure A is congruent to figure C.

That is \angle A\cong \angle B, \ \angle B\cong \angle C \  \text{then} \ \angle A\cong \angle C

From the above properties, it is clear that,

If ∠1 ≅ ∠2 then ∠2 ≅ ∠1 is symmetric property of congruence.

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3 years ago
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BartSMP [9]
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Elanso [62]

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Step-by-step explanation:

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Answer:

<h2>See below</h2>

Step-by-step explanation:

I can't drag and drop the graphs, but I can graph the equations shown. Then, all you will have to do is match the graphs shown the the graph that I will provide.

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Axis of symmetry is x = 0

Graph photo shown in file called equation 1 graph

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Axis of symmetry is x = 0

Graph photo shown in file called equation 2 graph

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Graph Properties:

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Graph photo shown in file called equation 3 graph

I'm always happy to help :)

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