Answer:
65625/4(x^5)(y²)
Step-by-step explanation:
Using binomial expansion
Formula: (n k) (a^k)(b ^(n-k))
Where (n k) represents n combination of k (nCk)
From the question k = 5 (i.e. 5th term)
n = 7 (power of expression)
a = 5x
b = -y/2
....................
Solving nCk
n = 7
k = 5
nCk = 7C5
= 7!/(5!2!) ------ Expand Expression
=7 * 6 * 5! /(5! * 2*1)
= 7*6/2
= 21 ------
.........................
Solving (a^k) (b^(n-k))
a = 5x
b = -y/2
k = 5
n = 7
Substituting these values in the expression
(5x)^5 * (-y/2)^(7-5)
= (3125x^5) * (-y/2)²
= 3125x^5 * y²/4
= (3125x^5)(y²)/4
------------------------------------
Multiplying the two expression above
21 * (3125x^5)(y²)/4
= 65625/4(x^5)(y²)
Answer:
c
Step-by-step explanation:
Answer:
sin(x - y) = 0.21
Step-by-step explanation:
we have the sin values which we need to get cos values
sin (A-B) = sin A cos B - sin B cos A
sin² A + cos² A = 1
sin x = 4/9
cos² x = 1 - sin² x = 1 - 16/81 = 65/81
cos² x = 65/81
cos x = √65/9
sin y = 1/4
cos² y = 1 - sin² y = 1 - 1/16 = 15/16
cos² y = 15/16
cos y = √15/4
sin(x − y) = sin x cos y - sin y cos x
sin(x - y) = 4/9 √15/4 - 1/4 √65/9
sin(x - y) = (4√15-√65)/36
sin(x - y) = 0.21
socratic Narad T
Answer:
6
Step-by-step explanation:
Given :
Sample size, n = 36
Sample variance, s² = 1296
The estimated standard error can be obtained using the relation :
Standard Error, S. E = standard deviation / √n
Standard deviation, s = √1296 = 36
S.E = 36/√36
S.E = 36/6
S.E = 6
Hence, estimated standard error = 6
