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Basile [38]
2 years ago
12

The area of triangle PQR is 273 cm. Given that PQ = 12.8cm and PQR = 107°, find QR.​

Mathematics
1 answer:
storchak [24]2 years ago
8 0

\text{Area of triangle} = \dfrac 12 \times PQ \times QR \times  \sin \angle PQR \\\\\\\implies  273= \dfrac 12 \times 12.8 \times QR \times \sin 107^{\circ}\\\\\implies 273 = 6.4 \sin 107^{\circ}  \times QR\\\\\\\implies QR = \dfrac{273}{6.4 \sin 107^{\circ}} = 44. 606~~ \text{cm}

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If A is 2x+2y=16, then x=3 and y=5

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If B is x+y=16, then x=5 and y=11

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Now, to find one interior angle in the decagon, divide 1440 by the number sides in our polygon (10).

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