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STALIN [3.7K]
3 years ago
10

One eighth to a decimal

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
8 0
Well if you see 1/8 is 100 divided by 8 and that is your number so.100 divided by eight is 12.5 and 12.5 is already a decimal so there you go

DochEvi [55]3 years ago
4 0
Divide the numerator by the denominator and you will get 0.125
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Identify the coefficients, terms, like terms, and constants in
igor_vitrenko [27]

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The coefficient is a number before a variable.

Here, the coefficient is 9.

The like terms are any terms that have the same variable.

Here, 9k and -k are like terms, and 7 and 4 are like terms as well.

Combine like terms:

8k+3

The constants are: 7 and 4 (Constants are numbers in an expression or equation)

After combining like terms, the constant became

3

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8 0
2 years ago
Ms. Maher made a recipe that calls for 144 fluid ounces. How many cups would that be?!?! A.
Lina20 [59]
Well,
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If there is 144 ounces...'
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Hope this helps :)
8 0
3 years ago
Read 2 more answers
What is the value of y?
Aleksandr [31]

We have an isosceles triangle with one angle 54 degrees and the other angles both labeled y degrees.


Triangle angles add to 180 degrees.


54 + y + y = 180


54 + 2y = 180


2y = 180 - 54 = 126


y = 126/2 = 63 degrees


Answer: 63 degrees


Check: 63+63+54=180 good



8 0
3 years ago
for the equation kx^2-(1+k)x+(3k+2)=0, the sum of the roots is twice their product. find k and the 2 roots​
Ostrovityanka [42]

Answer:

The value of k is \frac{-3}{5}

The roots are -1 and \frac{1}{3}

Step-by-step explanation:

In any quadratic equation ax^{2}+bx+c=0 the sum of its roots is \frac{-b}{a} and the product of its root is \frac{c}{a}

In the equation kx^{2}-(1+k)x+(3k+2)=0

The sum is \frac{--(1+k)}{k}=\frac{1+k}{k}

The product is \frac{3k+2}{k}

∵ The sum of the roots is twice their product

∴ \frac{k+1}{k}=2[\frac{3k+2}{k}]

∴ \frac{1+k}{k}=\frac{6k+4}{k}⇒Multiply both sides by k

1 + k = 6k + 4⇒ 1 - 4 = 6k - k

5k = -3 ⇒ k=\frac{-3}{5}

Use the value of k in the equation:

\frac{-3}{5}x^{2}-[1+\frac{-3}{5}]x+[(3)(\frac{-3}{5})+2]=0

\frac{-3}{5}x^{2}-\frac{2}{5}x+\frac{1}{5}=0⇒ Multiply equation by 5

-3x^{2}-2x+1=0⇒ Multiply equation by -1

3x^{2}+2x-1=0⇒ use factorization to find roots

(3x - 1)(x + 1) = 0

3x -1 = 0⇒ 3x = 1⇒ x = 1/3

x + 1 = 0⇒ x = -1

The roots are 1/3 and -1

6 0
3 years ago
What the equation of (1,4) and (0,1)
Doss [256]

Answer:

y = 3x + 1

Step-by-step explanation:

Use the slope formula and slope-intercept

7 0
3 years ago
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