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2 years ago

12

Write the equation of a line whose slope is -2 and passes through (-1,6). Write the answer in slope-intercept form.

2 answers:

erica [24]2 years ago

4 0

We are given an (X, Y) in (-1, 6). We are also given a slope of -2.

Start by plugging all those values into the slope intercept equation.

6 = -2*-1 + B

Solve for B.

B = 4

Now, all you have to do is put it back into the equation again, this time not using the (X,Y) we had initially, but just the slope (-2) and our new "B" value (5).

The resulting equation looks like this:

y= -2x + 4

And that's the answer.

goblinko [34]2 years ago

3 0

Y = mx + b
slope(m) = -2
(-1,6)....x = -1 and y = 6
now we sub and find b, the y int
6 = -2(-1) + b
6 = 2 + b
6 - 2 = b
4 = b

so ur equation is : y = -2x + 4 <==

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2 years ago

The number y of hits a new website receives each month can be modeled by y = 4070ekt, where t represents the number of months th

makvit [3.9K]

Answer:

<u><em>k = 0.2645</em></u>

Step-by-step explanation:

Given model:

y = 4070 $e^{kt}$

y = no. of hits website received = 9000 (in 3rd month)

t= no. of months website has been operational = 3

put in the above equation:

9000 = 4070 $e^{3k}$

$\frac{9000}{4070}$ = $e^{3k}$

$\frac{900}{407}$ = $e^{3k}$

<u><em>Taking natural logarithm on both sides, we get:</em></u>

$ln\frac{900}{407}$ = $ln(e^{3k})$

$ln\frac{900}{407}$ = 3k ln<em>e</em>

ln<em>e</em>=1

$ln \frac{900}{407}$ = 3k

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7 0

2 years ago

If 5^2x = 1, what is the value of 'x' ?

SVETLANKA909090 [29]

Answer:

x = 0

Step-by-step explanation:

5^0 is 1, meaning that x must equal to 0 for the answer to be 5^0.

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1 year ago

Read 2 more answers

Will mark brainliest

TEA [102]

Answer:

The width is 2.

Step-by-step explanation:

The equation is 2 x 3 x ? = 12.

It is 2 long

It is 3 in height

2 x 3 = 6

6 x 2 = 12

so 2 is the width.

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2 years ago

Simplify without the absolute value |x+3| ; if x>2

inna [77]

Answer:

$x+3$ if $x>2$

Step-by-step explanation:

Recall some following basic ideas about absolute value:

$|0|=0$ or I guess $-(0)=0$

$|3|=3$

$|-3|=-(-3)$ or just $3$ but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at $|x+3|$ alone for a second.

* $|x+3|=x+3$ if $x+3$ is positive or zero.

When is $x+3$ positive or zero? [greater than or equal to 0]

$x+3\ge 0$

Subtract 3 on both sides

$x\ge -3$

* $|x+3|=-(x+3)$ if $x+3$ is negative or zero.

When is $x+3$ negative or zero? [less or equal to 0]

$x+3\le 0$

Subtract 3 on both sides

$x\le -3$

So looking at the bullet points (the *), $x>2$ fits into the first inequality.

Therefore, $|x+3|=x+3$ .

8 0

2 years ago