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Doss [256]
3 years ago
10

Complete each operation question showing all steps, and reduce the final answer to lowest terms (improper fractions do not need

to be changed to mixed numbers as in grade 9, we work with improper fractions instead).

Mathematics
1 answer:
dlinn [17]3 years ago
4 0

All the answers, which are reduced to lowest terms, and the steps are in the images below (they’re in order based on the questions). I only answered questions <em>a</em> through <em>e </em>(not f), because it would only allow me to attach five photos. The answer for question <em>c</em> is in mixed numbers form because image said 4\frac{3}{10}, so as an improper fraction it’s \frac{43}{10}.

Hope this helps my friend! :)

You might be interested in
Please show how 1200.00 is an estimate of 31×43?
Vika [28.1K]
Ok so you round 31 to 30 and 43 to 40 and then you multiply 30 by 40 and get 1200. 1200 is the same thing as 1200.00 bc you can take off the zeros after the decimal and it will be the same. Hope this helped and if your still confused you let me know I'll try to explain it more.
4 0
3 years ago
Solve the equastion for x + 2 1/2 =10
Virty [35]

Answer:

x= 7 1/2

Step-by-step explanation:

Subtract the 1/2 to get it out of the way (whatever you do on one side of the = sign you have to do to the other)

So 10- 1/2= 9 1/2

Subtract the 2 to get it out of the way

9 1/2-2=

7 1/2

Hope it helped :)

8 0
1 year ago
The probability of getting a head when a biased coin is tossed is . The coin is tossed three times. Find the following probabili
S_A_V [24]

Answer:

a) P(three tails) = \frac{1}{8}

b) P(two tails followed by one head) = \frac{1}{8}

Step-by-step explanation:

coin is tossed three times so, outcome is

HHH, TTT, HTH, THH, HHT, THT, TTH, HTT.

Hence sample space will be

S = {HHH, TTT, HTH, THH, HHT, THT, TTH, HTT}

chance of getting three tails is '1' i.e. TTT

hence,

P(three tails) = \frac{1}{8}

two tails followed by one head is TTH

so, chance of getting that outcome is also '1'

hence,

P(two tails followed by one head) = \frac{1}{8}

6 0
2 years ago
Can you please show the working?
creativ13 [48]

The Price of Car A rounded to the Nearest £100 is £12400

The Price of Car B rounded to the Nearest £100 is £16800

The Price of Car C rounded to the Nearest £100 is £14600

Difference between the Rounded Price and Original Price of Car A :

⇒ (£12400 - £12380) = £20

Difference between the Rounded Price and Original Price of Car B :

⇒ (£16800 - £16760) = £40

Difference between the Rounded Price and Original Price of Car C :

⇒ (£14600 - £14580) = £20

From the above, We can Notice that :

The Price of Car B changes by the greatest amount.

4 0
3 years ago
I answered wrong what’s the right answer?
olganol [36]
The answer is CBE :)))))
6 0
3 years ago
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