Answer:
−7r^(2)+12r+10x−18
Step-by-step explanation:
Grab the original equation: 10x+7r−r^(2)−6r^(2)−18+5r
For subtraction bits, treat them as negatives: 10x+7r+−r^(2)+−6r^(2)+−18+5r
Combine like terms: (−r^2+−6r^2)+(7r+5r)+(10x)+(−18)
Simplify that, and you get your final answer: −7r^(2)+12r+10x+−18
Answer:
One real root
Step-by-step explanation:
By the fundamental theorem of algebra, an nth degree polynomial has n-possible real roots.
If there are complex roots, then the the complex roots come in pairs.
Therefore the number of possible real roots of
are 3 real roots with no complex pairs or 1 real root with a complex pair.
By Descartes rule of signs, there is only one change of sign in the polynomial (+ to -).
Hence there is only one positive real root.

There is change is sign two times but we can not have even number of real roots for this polynomial
Therefore there is only real root.
It's really easy just divide 800/50
the answer is 16 times
Sample Space = {HH,HT,TH,TT} - Hope this helps!
Could you maybe right it down so i can like... understand it