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Lelu [443]
3 years ago
13

If the triangle ABC=JKL and ACB=12,KL=6cm,and AC=8.5cm what is BC

Mathematics
1 answer:
Illusion [34]3 years ago
5 0
BC is equal to KL so there for BC is 6 cm
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What is equavilent to (10x+7r-r^(2))+(-6r^(2)-18+5r)
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Answer:

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Step-by-step explanation:

Grab the original equation: 10x+7r−r^(2)−6r^(2)−18+5r

For subtraction bits, treat them as negatives: 10x+7r+−r^(2)+−6r^(2)+−18+5r

Combine like terms: (−r^2+−6r^2)+(7r+5r)+(10x)+(−18)

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goldfiish [28.3K]

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By the fundamental theorem of algebra, an nth degree polynomial has n-possible real roots.

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Therefore the number of possible real roots of f(x)=x^3+2x^2+2x-5 are 3 real roots with no complex pairs or 1 real root with a complex pair.

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