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BartSMP [9]
4 years ago
13

What is the sample space when a coin is tossed twice?

Mathematics
2 answers:
Oksana_A [137]4 years ago
8 0
Sample Space = {HH,HT,TH,TT} - Hope this helps!
Nitella [24]4 years ago
5 0

Answer:

HH, HT, TT, TH

Step-by-step explanation:

Your welcome.

USA testprep squad waz good

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Find the slope of the containing (5,-2) and (-3,4)
White raven [17]

Answer:

-3/4

Step-by-step explanation:

Let x₁ = -3      x₂ = 5       y₁ = 4          y₂ = -2

The slope of a linear function is defined by:

  • m = rise / run
  •    = (y₂ - y₁) / (x₂ - x₁)
  •    = (-2 - 4) / (5 - (-3))
  •    = (-6) / (8)
  •    = -3/4

4 0
3 years ago
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WILL UPVOTE!<br> Factor the expression.<br> x^2 -12x +36 =
svlad2 [7]
(x-6)(x+6) this is the answer my student thought of in class
5 0
3 years ago
Help with math Plsss I don't understand how to do this (I got this wrong but I have another try)​
Anuta_ua [19.1K]
<h3>Answer: 920</h3>

=================================================

Explanation:

The front face is a triangle with area of base*height/2 = 15*8/2 = 60 square feet.

The back face is identical to the front face, so we have another 60 square feet.

The left rectangular wall is 20 ft by 8 ft tall. Its area is 20*8 = 160 ft^2

The right slanted rectangular face is 20 ft by 17 ft. Its area is 20*17 = 340 ft^2

Lastly, the bottom rectangle floor is 15 ft by 20 ft to give an area of 15*20 = 300 ft^2

------------------

To summarize so far

  • Front face = 60 ft^2
  • Back face = 60 ft^2
  • Left face = 160 ft^2
  • Right slanted face = 340 ft^2
  • Bottom floor = 300 ft^2

Add up those areas to get the overall surface area.

60+60+160+340+300 = 920

6 0
2 years ago
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What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1
Ratling [72]

Answer:

\sqrt3

Step-by-step explanation:

To find:

The value of tan60^\circ = ?

Solution:

Kindly consider the equilateral \triangle ABC as attached in the answer area.

Let the side of triangle = a units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = \frac{a}{2}

Using Pythagorean Theorem in \triangle ABD:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}

Side AD = \frac{\sqrt3}{2}a

Using Trigonometric ratio:

tan\theta = \dfrac{Perpendicular}{Base}

tanB = \dfrac{AD}{BD}

Putting the values of AD and BD:

tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}

5 0
3 years ago
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I need help mann I’m stuck
lord [1]

Answer:

slope -1/3

y- intercept 1

3 0
3 years ago
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