Answer:
yes
Step-by-step explanation:
Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
Answer:
its 66 :)
Step-by-step explanation:
I used a calculator:D
C $1.00
because 1/3 of 15 coins are 5 dimes
15 - 5 = 10 nickels
10 + 5 = 15 coins.
5 dimes= .50 cents
10 nickels= . 50 cents
.50 + .50 = $1.00
$1.00 is C.
*Hope this helped :)