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amm1812
3 years ago
10

???????? Why ir why not

Mathematics
2 answers:
sertanlavr [38]3 years ago
5 0

I guess the answer is no because if it is not a straight line it won't make a function. but sometimes a curve make a function when it passes through y and x axises

i hope it helps u

denpristay [2]3 years ago
4 0

yes because it passes the vertical line test

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Work out the value of (10^4)^2​
Yuri [45]

Answer:

100000000

Step-by-step explanation:

(10^4)^2                                                   key =

{(2.5)^4}^2                                                       . = times

(2^4 . 5^4)^2

(2^4) ^2 (5^4)^2

2^4 ^.2. 5^4^.2

2^8 . 5^8

256. 390625

100000000

4 0
3 years ago
Tim has $20 to buy snacks for 12 people in an office. Each person will get one snack. Tim is buying bags of pretzels that cost $
Greeley [361]

Answer:

  8 bags of pretzels

Step-by-step explanation:

Let x represent the number of bags of pretzels Tim buys. We assume he spends exactly $20 on exactly 12 bags of snack food. Then his purchase is ...

  1.50x + 2.00(12-x) = 20.00

  -0.50x +24.00 = 20.00 . . . eliminate parentheses, collect terms

  -0.50x = -4.00 . . . . . . . . . . .subtract 24

  x = 8 . . . . . . . . . . divide by -0.50

Tim will buy 8 bags of pretzels.

4 0
3 years ago
Plzz help i dont understand
tangare [24]
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7 0
3 years ago
Which of the following pairs of points are both solutions to the equation 2x-5y=6 ? and and and and
zhannawk [14.2K]

Answer:

Any points on the line y=2/5 x - 6/5. See picture below.

Step-by-step explanation:

Convert the equation to slope intercept form and graph it.

2x - 5y = 6

-5y = 6 - 2x

y = -2/-5 x + 6/-5

y=2/5 x - 6/5.

Locate each of the points listed on the graph. If they are a part of the line, then they are solutions.

3 0
3 years ago
Let P be the parabola with focus (0,4) and directrix y=x.Write an equation whose graph is a parabola with a vertical directrix t
prisoha [69]

Answer:

y²=4√2.x

Step-by-step explanation:

The focus is at (0,4) and directrix is y=x or x-y =0, for a parabola P.

The distance between the focus and the directrix of the parabola P is

\frac{ |0-4| }{\sqrt{(1)^{2}+(-1)^{2}  } }=\frac{4}{\sqrt{2} }

{Since the perpendicular distance of a point (x1, y1) from the straight line ax+by+c =0 is given by \frac{ |ax1+by1+c| }{\sqrt{a^{2}+b^{2}  } } }

Let us assume that the equation of the parabola which is congruent with parabola P is y²=4ax

{Since the parabola has vertical directrix}

Hence, the distance between focus and the directrix is 2a = \frac{4}{\sqrt{2} }, {Two parabolas are congruent when the distances between their focus and the directrix are same}

⇒ a=√2

Therefore, the equation of the parabola is y²=4√2.x (Answer)

3 0
3 years ago
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