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Simora [160]
3 years ago
14

A pharmaceutical company is conducting a study on whether or not their new vaccine is effective in preventing chicken pox. The r

esearchers rejected the null hypothesis and stated that the vaccine was effective. However, subsequent studies found out that the vaccine did not have any effect on combating chicken pox. What type of error did the researchers make
Mathematics
1 answer:
Fed [463]3 years ago
5 0

Answer:

The answer is "Type 1 error".

Step-by-step explanation:

The error of type I, frequently known as a 'false positive': its error in judgment that perhaps a null hypothesis is simply rejected. This is the mistake of accepting a possible (actual interest hypothesis) hypothesis whenever the results could be attributed to chance since the researchers deny, if valid, the null hypothesis.

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Make r the subject of t = 6r^2 + 6
SpyIntel [72]

First step, divide 6 from both sides.

t/6=r^2+1

second step, subtract 1 from both sides

t/6 -1=r^2

Now take the square root of each side.

\sqrt{\frac{t}{6}-1}=r

Done!

3 0
3 years ago
A horticulturist working for a large plant nursery is conducting experiments on the growth rate of a new shrub. Based on previou
valkas [14]

Answer:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

Step-by-step explanation:

Information given

\bar X=1.8 represent the sample mean for the growth

s=0.5 represent the sample standard deviation    

n=48 sample size    

\mu_o =2 represent the value that we want to compare

\alpha=0.01 represent the significance level

t would represent the statistic    

p_v represent the p value

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 2cm per week, the system of hypothesis are :    

Null hypothesis:\mu \geq 2    

Alternative hypothesis:\mu < 2    

Since we don't know the population deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

Replacing the info given we got:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

6 0
3 years ago
15% 40% as whole numbers
Alex17521 [72]

Answer: Not possible

Step-by-step explanation: A whole number is an integer or a number without fractions. Both 15% and 40% are less than 1 since they are less than 100%; therefore, it is impossible to express them as whole numbers. They can only be expressed as the mixed numbers of 0.15 and 0.4, or 15/100 and 40/100.

3 0
3 years ago
Read 2 more answers
Solve using square roots
blsea [12.9K]
You can not see the problem
8 0
3 years ago
If 160,000÷n=4 then what is n?
shusha [124]
160,000/4 = n
n = 40,000

Answer: n = 40,000
8 0
3 years ago
Read 2 more answers
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