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noname [10]
3 years ago
12

1. Jessie colored a poster. She colored

Mathematics
1 answer:
kiruha [24]3 years ago
6 0

Answer:

2/5 = 1/10

Step-by-step explanation:

multiply the numerator and denominator by 2 and get 1/10

You might be interested in
Whats 1.64 as a mixed number in simplest form
raketka [301]
It is 1 16/25

Hope it helps ;-)
8 0
3 years ago
If the given values in a right triangle are cos A =
Vlad1618 [11]
See the picture attached to better understand the problem

we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²---->  equation 1

applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2

substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2

the answer is
the hypotenuse is (3√2)/2

5 0
3 years ago
The Anderson's are driving 2,563 miles to the beach. They plan to drive 325 miles a day. How many days will it take the Anderson
12345 [234]

Answer:

Around 8 days

Step-by-step explanation:

Divide 325 from 2,563

2563 / 325 = 7.888

Round that number

3 0
3 years ago
In a recent survey about what food was your favorite take-out, it was determined that 40% of students preferred pizza, 32% of st
Nataliya [291]

Answer:

576 students choose cheeseburgers

Step-by-step explanation:

Given: In a survey, it was determined that 40% of students preferred pizza, 32% of students preferred cheeseburgers, and 28% of students preferred tacos.

To find: Number of students out of 1800 who choose cheeseburgers

Solution:

Percentage of students who preferred cheeseburgers = 32%

Total number of students = 1800

Number of students out of 1800 who choose cheeseburgers = \frac{32}{100}(1800)=576

8 0
3 years ago
The line L is a tangent to the curve with equation y= 4x^2 +1 . The line L cuts the y axis at (0,8) and has a positive gradient.
sergeinik [125]

A generic point on the graph of the curve has coordinates

(x, 4x^2+1)

The derivative gives us the slope of the tangent line at a given point:

f(x) = 4x^2+1 \implies f'(x) = 8x

Let k be a generic x-coordinate. The tangent line to the curve at this point will pass through (k, 4k^2+1) and have slope 8k

So, we can write its equation using the point-slope formula: a line with slope m passing through (x_0, y_0) has equation

y-y_0 = m(x-x_0)

In this case, (x_0, y_0)=(k, 4k^2+1) and m=8k, so the equation becomes

y-4k^2-1 = 8k(x-k)

We can rewrite the equation as follows:

y-4k^2-1 = 8k(x-k) \iff y = 8kx - 8k^2+4k^2+1 \iff y = 8kx-4k^2+1

We know that this function must give 0 when evaluated at x=0:

f(x) = 8kx-4k^2+1 \implies f(0) = -4k^2+1 = 8 \iff -4k^2 = 7 \iff k^2 = -\dfrac{7}{4}

This equation has no real solution, so the problem looks impossible.

5 0
3 years ago
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