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Digiron [165]
2 years ago
11

A line has a slope of 11 and passes through the point (5,7). Which of these is an equation for the line? O A. y-7 = -11(x - 5) B

. y + 7 = 11(x + 5) O C. y-5 = -11(x - 7) O D. y - 7 = 11(x - 5) SUBMIT​
Mathematics
1 answer:
pshichka [43]2 years ago
6 0

Answer:

D. y - 7 = 11(x - 5)

Step-by-step explanation:

Use point slope form, y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

Plug in the given slope and point:

y - y1 = m(x - x1)

y - 7 = 11(x - 5)

So, the correct answer is D. y - 7 = 11(x - 5)

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Shtirlitz [24]
If there is no expression, it surely is equal to 0.
5 0
3 years ago
Read 2 more answers
What is the value of x in: 4x+3y=12 and 2x-3y=-30 *
NNADVOKAT [17]

Answer:

The value would be

Step-by-step explanation:

What is the value of x in: 4x+3y=12 and 2x-3y=-30 *

4x + 3y

The answer is x = 2 - 3y = 4

3y = 30

So 2x + 3y = 12 is

X = 3 - 3y/4

2x - 3y = 30

X = 15 + 3y/2

Hope it help : ) Please Rate it for me!

Have a Great Day and Winter Break!

6 0
2 years ago
Rewrite cot 80° in terms of its cofunction.
zysi [14]

Answer:

tan 10 degrees.

Step-by-step explanation:

tan x = cot (90 - x) so:

cot 80 = cot (90 - 10)

= tan 10.

8 0
3 years ago
The average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 in
Murrr4er [49]

Answer:

Probability that average height would be shorter than 63 inches = 0.30854 .

Step-by-step explanation:

We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.

Also, a random sample of 4 women from this population is taken and their average height is computed.

Let X bar = Average height

The z score probability distribution for average height is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 64 inches

           \sigma = standard deviation = 4 inches

           n = sample of women = 4

So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)

P(X bar < 63) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{63-64}{\frac{4}{\sqrt{4} } } ) = P(Z < -0.5) = 1 - P(Z <= 0.5)

                                                        = 1 - 0.69146 = 0.30854

Hence, it is 30.85%  likely that average height would be shorter than 63 inches.

7 0
3 years ago
F(x)=x^4-6x^3+5x^2+24x-36 <br><br>what are the x-intercepts of f(x)?
Art [367]

(-2, 0), (2, 0), and (3, 0)

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6 0
3 years ago
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