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Digiron [165]
3 years ago
11

A line has a slope of 11 and passes through the point (5,7). Which of these is an equation for the line? O A. y-7 = -11(x - 5) B

. y + 7 = 11(x + 5) O C. y-5 = -11(x - 7) O D. y - 7 = 11(x - 5) SUBMIT​
Mathematics
1 answer:
pshichka [43]3 years ago
6 0

Answer:

D. y - 7 = 11(x - 5)

Step-by-step explanation:

Use point slope form, y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

Plug in the given slope and point:

y - y1 = m(x - x1)

y - 7 = 11(x - 5)

So, the correct answer is D. y - 7 = 11(x - 5)

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inna [77]

Step-by-step explanation:

Complete question is attached.

Answer:

a) ED = 6.5 cm

b) BE = 14.4 cm

Step-by-step explanation:

From the triangle, we are given the following dimensions:

AB = 20 cm

BC = 5 cm

CD = 18 cm

AE = 26 cm

We are asked to find length of sides ED and BE.

a) Find length of ED.

From the triangle Let's use the equation:

\frac{AB}{BC} = \frac{AE}{ED}BCAB=EDAE

Cross multiplying, we have:

AB * ED = AE * BC

From this equation, let's make ED subject of the formula.

ED = \frac{AE * BC}{AB}ED=ABAE∗BC

Let's substitute figures,

ED = \frac{26 * 5}{20}ED=2026∗5

ED = \frac{130}{20} = 6.5ED=20130=6.5

Therefore, length of ED is 6.5 cm.

b) To find length of BE, let's use the equation:

\frac{AB}{AC} = \frac{BE}{CD}ACAB=CDBE

Cross multiplying, we have:

AB * CD = AC * BE

Let's make BE subject of the formula,

BE = \frac{AB * CD}{AC}BE=ACAB∗CD

From the triangle, length AC = AB + BC.

AC = 20 + 5 = 25

Substituting figures, we have:

BE = \frac{20 * 18}{25}BE=2520∗18

BE = \frac{360}{25} = 14.4BE=25360=14.4

Therefore, length Of BE is 14.4cm

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