The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
<h3>What is the derivative of the function g(x) by virtue of the Fundamental theorem of calculus as given in the task content?</h3>
g(x) = Integral; √2 ln(t) dt (with the upper and lower limits e^x and 1 respectively).
Since, it follows from the Fundamental theorem of calculus that given an integral where;
Now, g(x) = Integral f(t) dt with limits a and x, it follows that the differential of g(x);
g'(x) = f(x).
Consequently, the function g'(x) which is to be evaluated in this scenario can be determined as:
g'(x) = = 1
The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
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Answer:
- 4 ≤ x < 2
Step-by-step explanation:
The interval is [ - 4, 2 )
The bracket on the left side indicates x can equal - 4
The parenthesis on the right side indicates x cannot equal 2
Thus the inequality represented by the graph is
- 4 ≤ x < 2
Answer:
X = 100
Step-by-step explanation:
X + 20 over 4 = 30
1/4x + 5 = 30
-5 -5
1/4x = 25
multiply both sides by 4
x = 100
<h2>Hey there! </h2>
<h2>The accurate answer is:</h2>
<h3>Option Y</h3>
<h2>Hope it help you </h2>