1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Blizzard [7]
3 years ago
13

HeLp Me PlEaSe , Ill MaRk YoU bRaInLiEsT !

Chemistry
1 answer:
Musya8 [376]3 years ago
3 0

Answer:

are you aking an NWEA?

Explanation:

You might be interested in
The way it can be determined which type of atom we have is to figure out____are contained within the nucleus of the atom A.elect
Dima020 [189]

protons and neutrons are in the nucleus electrons surround the atom and i have no idea what positrons are i just know they arent in an atom so your answer is B and C

6 0
3 years ago
a balloon filled with a volume of 1.50 L is compressed to a volume of 0.50 L at a constant rate of temperature. if the initial p
Arisa [49]

Answer:

New pressure P2 = 4.95 atm

Explanation:

Given:

Old volume V1 = 1.50 L

New volume V2 = 0.50 L

Old pressure P1 = 1.65 atm

Find:

New pressure P2

Computation:

P1V1 = P2V2

So,

(1.50)(1.65) = (0.50)(P2)

New pressure P2 = 4.95 atm

5 0
3 years ago
What are the safety procedures for nuclear accidents nowadays?
Zigmanuir [339]

Explanation:

Take shelter in a hard wall building

Close doors and windows cut off ventilation

4 0
3 years ago
How many grams of iron(II) chloride are needed to produce 44.3 g iron(II) phosphate in the presence of excess sodium phosphate?
zalisa [80]

Answer:

47.2 g

Explanation:

Let's consider the following double displacement reaction.

3 FeCl₂ + 2 Na₃PO₄ → Fe₃(PO₄)₂ + 6 NaCl

The molar mass of Fe₃(PO₄)₂ is 357.48 g/mol. The moles corresponding to 44.3 g are:

44.3 g × (1 mol / 357.48 g) = 0.124 mol

The molar ratio of Fe₃(PO₄)₂ to FeCl₂ is 1:3. The moles of FeCl₂ are:

3 × 0.124 mol = 0.372 mol

The molar mass of FeCl₂ is 126.75 g/mol. The mass of FeCl₂ is:

0.372 mol × (126.75 g/mol) = 47.2 g

5 0
3 years ago
If iodine-131 has a half-life of 8 days, how much of a 64.0 g sample of iodine-131 will remain after 32 day?
Mariulka [41]

Answer:

4 g OF IODINE-131 WILL REMAIN AFTER 32 DAYS.

Explanation:

Half life (t1/2) = 8 days

Original mass (No) = 64 g

Elapsed time (t) = 32 days

Mass remaining (Nt) = ?

Using the half life equation we can obtain the mass remaining (Nt)

Nt = No (1/2) ^t/t1/2

Substituting the values, we have;

Nt = 64 * ( 1/2 ) ^32/8

Nt = 64 * (1/2) ^4

Nt = 64 * 0.0625

Nt = 4 g

So therefore, 4 g of the iodine-131 sample will remain after 32 days with its half life of 8 days.

8 0
3 years ago
Other questions:
  • Which of these is an example of a chemical reaction that occurs at a very fast rate?
    6·2 answers
  • What happens when organisms decompose, what happens to carbon
    14·1 answer
  • how many moles of sodium are needed to react with sulfuric acid to produce 3.75 moles of sodium sulfate according to the followi
    9·1 answer
  • In sodium chloride, which atom loses an electron?
    13·2 answers
  • What does the empirical formula of a compound represent?
    13·1 answer
  • Metals that really react with cold water are __________ and __________
    14·1 answer
  • If the temperature of one mole of gas increases while its volume decreases, would you expect the gas pressure to increase, decre
    11·1 answer
  • In an experiment Nyla collected the following information about a solution made from a certain food:
    14·1 answer
  • Issac Newton là người đã khám phá ra lực gì?
    10·1 answer
  • Compare the reactions in mitochondria with glycolysis​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!