9514 1404 393
Answer:
{-2, 0, 1, 3}
Step-by-step explanation:
The domain is the list of the x-values in the (x, y) pairs:
{-2, 0, 1, 3}
Answer:
1 / ( 243s^40 )
Step-by-step explanation:
For this problem, we need to know that a negative exponent simply can be rewritten in the opposing part of the fraction, for this case, the denominator. So we can simplify as shown:
(3s^8)^-5
= 1 / (3s^8)^5
= 1 / 3^5 * s^8^5
= 1 / 243 * s^40
= 1 / ( 243s^40 )
Cheers.
Given that <span>For
a certain model of car the distance
required to stop the vehicle if
it is traveling at
mi/h is given by the formula
![d=v+\frac{v^2}{20}, where [tex]d](https://tex.z-dn.net/?f=d%3Dv%2B%5Cfrac%7Bv%5E2%7D%7B20%7D%2C%20where%20%5Btex%5Dd%20)
is measured in feet.
If Kerry wants her stopping distance not to exceed 75
ft, then the range of speeds (in mi/h) can she travel is obtained as follows:
Therefore, the range of speed she can travel is
</span>
Answer:
-68 is your answer
Step-by-step explanation:
Remember to follow PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
First, solve each parenthesis
(-21 x 3) = -63
(15/-3) = -5
Next, add
(-63) + (-5) = -63 - 5 = -68
-68 is your answer
~
Answer:
The interquartile range is 5.
Step-by-step explanation:
Ah, a throwback to interquartile range... let me help :)
4,5,6,8,9,10,11,12
First, you need to know how to use the IQR. The interquartile range is basically known as the process of subtracting the upper quartile and the lower quartile of a set of data. The lower quartile should be written as Q1, and the upper quartile would be labeled as Q3. This would make the midpoint (median) data set Q2, and the highest possible point would be labeled Q4. Next, you have to always understand what you are looking at. For example, let's split the set 5,6,7,8,9,10,11,12 into groups. 5 and 6 would be Q1, 7 and 8 would be Q2, 9 and 10 would be Q3, and last but not least, 11 and 12 would be labeled as Q4. Now take Q1 and subtract it from Q3 and that is how you get your IQR.
