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In-s [12.5K]
3 years ago
8

18 times what is 504

Mathematics
2 answers:
Elena-2011 [213]3 years ago
7 0

Answer:

28

Step-by-step explanation:

divide 504/18=28

luda_lava [24]3 years ago
3 0
<h2><em>To figure an equation such as this, you need to do the reverse math. 504 / 18 = 28. Check your answer. 18 x 28 = 504.</em></h2><h2><em>28 is your answer.</em></h2><h2><em>Hope this helps and have a nice day! o/</em></h2>
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How to calculate this using a quadratic equation? <br><br> 1.56= (x+0)(x+0) / (2-x)(1-x)
Hoochie [10]

Answer:

x = ((18 sqrt(755833) - 17050)^(1/3) - (284 (-1)^(2/3))/(8525 - 9 sqrt(755833))^(1/3))/(15 2^(2/3)) + 1/3 or x = 1/3 + 142/15 ((-2)/(8525 - 9 sqrt(755833)))^(1/3) - 1/15 ((-1)/2)^(1/3) (9 sqrt(755833) - 8525)^(1/3) or x = 1/3 - (2^(1/3) (8525 - 9 sqrt(755833))^(2/3) + 284)/(15 2^(2/3) (8525 - 9 sqrt(755833))^(1/3))

Step-by-step explanation:

Solve for x over the real numbers:

1.56 = ((x + 0) (x + 0) (1 - x))/(2 - x)

1.56 = 39/25 and ((x + 0) (x + 0) (1 - x))/(2 - x) = (x^2 (1 - x))/(2 - x):

39/25 = (x^2 (1 - x))/(2 - x)

39/25 = ((1 - x) x^2)/(2 - x) is equivalent to ((1 - x) x^2)/(2 - x) = 39/25:

(x^2 (1 - x))/(2 - x) = 39/25

Cross multiply:

25 x^2 (1 - x) = 39 (2 - x)

Expand out terms of the left hand side:

25 x^2 - 25 x^3 = 39 (2 - x)

Expand out terms of the right hand side:

25 x^2 - 25 x^3 = 78 - 39 x

Subtract 78 - 39 x from both sides:

-25 x^3 + 25 x^2 + 39 x - 78 = 0

Multiply both sides by -1:

25 x^3 - 25 x^2 - 39 x + 78 = 0

Eliminate the quadratic term by substituting y = x - 1/3:

78 - 39 (y + 1/3) - 25 (y + 1/3)^2 + 25 (y + 1/3)^3 = 0

Expand out terms of the left hand side:

25 y^3 - (142 y)/3 + 1705/27 = 0

Divide both sides by 25:

y^3 - (142 y)/75 + 341/135 = 0

Change coordinates by substituting y = z + λ/z, where λ is a constant value that will be determined later:

341/135 - 142/75 (z + λ/z) + (z + λ/z)^3 = 0

Multiply both sides by z^3 and collect in terms of z:

z^6 + z^4 (3 λ - 142/75) + (341 z^3)/135 + z^2 (3 λ^2 - (142 λ)/75) + λ^3 = 0

Substitute λ = 142/225 and then u = z^3, yielding a quadratic equation in the variable u:

u^2 + (341 u)/135 + 2863288/11390625 = 0

Find the positive solution to the quadratic equation:

u = (9 sqrt(755833) - 8525)/6750

Substitute back for u = z^3:

z^3 = (9 sqrt(755833) - 8525)/6750

Taking cube roots gives (9 sqrt(755833) - 8525)^(1/3)/(15 2^(1/3)) times the third roots of unity:

z = (9 sqrt(755833) - 8525)^(1/3)/(15 2^(1/3)) or z = -1/15 (-1/2)^(1/3) (9 sqrt(755833) - 8525)^(1/3) or z = ((-1)^(2/3) (9 sqrt(755833) - 8525)^(1/3))/(15 2^(1/3))

Substitute each value of z into y = z + 142/(225 z):

y = 1/15 ((9 sqrt(755833) - 8525)/2)^(1/3) - 142/15 (-1)^(2/3) (2/(8525 - 9 sqrt(755833)))^(1/3) or y = 142/15 ((-2)/(8525 - 9 sqrt(755833)))^(1/3) - 1/15 ((-1)/2)^(1/3) (9 sqrt(755833) - 8525)^(1/3) or y = 1/15 (-1)^(2/3) ((9 sqrt(755833) - 8525)/2)^(1/3) - 142/15 (2/(8525 - 9 sqrt(755833)))^(1/3)

Bring each solution to a common denominator and simplify:

y = ((18 sqrt(755833) - 17050)^(1/3) - (284 (-1)^(2/3))/(8525 - 9 sqrt(755833))^(1/3))/(15 2^(2/3)) or y = 142/15 ((-2)/(8525 - 9 sqrt(755833)))^(1/3) - 1/15 ((-1)/2)^(1/3) (9 sqrt(755833) - 8525)^(1/3) or y = -(2^(1/3) (8525 - 9 sqrt(755833))^(2/3) + 284)/(15 2^(2/3) (8525 - 9 sqrt(755833))^(1/3))

Substitute back for x = y + 1/3:

Answer: x = ((18 sqrt(755833) - 17050)^(1/3) - (284 (-1)^(2/3))/(8525 - 9 sqrt(755833))^(1/3))/(15 2^(2/3)) + 1/3 or x = 1/3 + 142/15 ((-2)/(8525 - 9 sqrt(755833)))^(1/3) - 1/15 ((-1)/2)^(1/3) (9 sqrt(755833) - 8525)^(1/3) or x = 1/3 - (2^(1/3) (8525 - 9 sqrt(755833))^(2/3) + 284)/(15 2^(2/3) (8525 - 9 sqrt(755833))^(1/3))

3 0
3 years ago
Laurie had three $2 off coupons for the mini-golf course, but everybody else had to pay $9 per person, the full price. What was
Ahat [919]

Answer:

D

Step-by-step explanation:

9x8=71

2x3=6

71-6=66

6 0
2 years ago
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How many groups of 2 people can you form with 6 people
GaryK [48]

Answer:3

Step-by-step explanation:

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Examine the linear table to find the slope, y-intercept, and write the equation for this linear relationship ​. NEED HELP PLEASE
gizmo_the_mogwai [7]

Answer:

y = \frac{4}{3} x + 17  

Step-by-step explanation:

The table shows a set of x and y values, thus showing a set of points we can use to find the equation.

1) First, find the slope by using two points and substituting their x and y values into the slope formula, \frac{y_2-y_1}{x_2-x_1}. I chose (-3, 13) and (0,17), but any two points from the table will work. Use them for the formula like so:

\frac{(17)-(13)}{(0)-(-3)} \\= \frac{17-13}{0+3} \\= \frac{4}{3}

Thus, the slope is \frac{4}{3}.

2) Next, identify the y-intercept. The y-intercept is where the line hits the y-axis. All points on the y-axis have a x value of 0. Thus, (0,17) must be the y-intercept of the line.

3) Finally, write an equation in slope-intercept form, or y = mx + b format. Substitute the m and b for real values.

The m represents the slope of the equation, so substitute it for \frac{4}{3}. The b represents the y-value of the y-intercept, so substitute it for 17. This will give the following answer and equation:

y = \frac{4}{3} x + 17

7 0
2 years ago
Consider a circle whose size can vary. The circumference of the circle is always 2 π 2π times as large as its radius. Let r r re
Alenkasestr [34]

Answer: C=2\pi r

Step-by-step explanation:

Let be "C" the circumference of the circle (in feet) and "r" the radius of the circle (in feet).

Based on the information provided in the problem, you know that the circumference of the circle is always 2\pi as large as its radius.

Notice that this indicates a multiplication. Then, this means that the circumference of the circle is always equal to 2\pi by "r".

Based on this, you can write the following formula that expresses the circumference "C" in terms of the radius "r":

C=2\pi r

4 0
2 years ago
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