800×0.14=112
112+15=127
(127÷800)*100==15.88%
Answer:
I think it is -10
Step-by-step explanation:
Using a^m*a^n=a^(m+n)
b=(m+n)
In this question,
m= -8 and n= -2
so b= (m+n)=(-8+-2) = -10
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Answer: Choice B 
</h3>
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Work Shown:
Angle theta is between 0 and pi/2, so this angle is in quadrant Q1.
Square both sides of the given equation

Then use the pythagorean trig identity to get

Answer:
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