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valentina_108 [34]
3 years ago
7

What 3 consecutive integers equal 84

Mathematics
2 answers:
Murrr4er [49]3 years ago
5 0

First represent your 3 consecutive integers as follows.

X ⇒ <em>first integer</em>

X + 1 ⇒ <em>second integer</em>

X + 2 ⇒ <em>third integer</em>

<em />

Since their sum is 84, our equation reads x + (x + 1) + (x + 2) = 84.

Simplifying on the left side we get 3x + 3 = 84.

Now subtract 3 from both sides to get 3x = 81.

Dividing both sides by 3, we find that <em>x = 27</em>.

Finally, make sure you list all your answers.

If <em>x </em>is 27 then <em>x </em>+ 1 is 28 and <em>x </em>+ 2 is 29.

TiliK225 [7]3 years ago
3 0

Answer:

27 + 28 + 29 = 84

Step-by-step explanation:

Let the three consecutive integers be x +1, x+2 and x+3

Thus,

(x + 1) + (x + 2) + (x + 3) = 84

Remove the brackets

x + 1 + x + 2 + x + 3 = 84

Group the like terms

x + x + x + 1 + 2 + 3 = 84

3x + 6 = 84

To make 3x subject of formula, subtract 6 from both sides of the equation thus,

3x + 6 - 6 = 84 - 6

3x = 78

Divide through by 3

\frac{3x}{3}  =  \frac{78}{3}

x = 26

Since x = 26

x + 1 = 26 + 1 = 27

x + 2 = 26 + 2 = 28

x + 3 = 26 + 3 = 29

Therefore, the three consecutive integers are 27, 28 and 29

Check

27 + 28 + 29 = 84

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Step-by-step explanation:

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Answer:

m<2

Step-by-step explanation:

To get to this, you first need to move the variable to one side, so you could subtract m from both sides to make the equation 16>7m+2. Next, you subtract 2 from both sides to make the equation into 14>7m. Finally, you would divide 7 from both sides to get 2>m, or m<2.

Hope this helps!

5 0
3 years ago
heights of statistics students were obtained by a teacher as part of an experiment conducted for the class. The last digit of th
hammer [34]

Answer:

1) B. The height appear to be reported because there are disproportionately more 0s and 5s.

2) A. They are likely not very accurate because they appear to be reported.

Step-by-step explanation:

The distribution table is shown below:

Last Digit           Frequency

     0                          9

     1                           1

     2                          1

     3                          3

     4                          1

     5                         11

     6                          1

     7                          0

     8                          3

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1. Based on the distribution table, we see a very disproportionate distribution. There is a high frequency of 0's and 5's. This lays credence to the heights being reported rather than measured. As such, option B is the correct answer

<u>B. The height appear to be reported because there are disproportionately more 0s and 5s</u>.

2. Since the heights were reported and not measured, they are most certainly not accurate. The conclusion is that the result is not accurate. As such, option A is the correct answer

<u>A. They are likely not very accurate because they appear to be reported</u>.

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Once an outlier is detected in a set of data, we can do the following to them:

  • Discard the outlier
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  • Consider the distribution given

We may have a set of data where some of the <em>values are far in distance from the majority of the data</em>. The set of such data are known as an outlier.

For example, give the set of data;

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45 can be considered as an outlier since the <em>distance of data</em><em> to all other data is</em><em> large</em><em>.</em>

Once an outlier is detected in a set of data, we can do the following to them:

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60*80%=

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