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mylen [45]
4 years ago
7

A ball falling through the air has what?

Physics
1 answer:
AysviL [449]4 years ago
8 0
A ball falling through the air has a mass, a density, a volume...it is facing air resistance and is being acted on by gravity...it is accelerating and gaining velocity...and it is increasing in kinetic energy.
I suppose out of all those the biggest thing the ball has in this case is ENERGY. There are two main types to focus on...

Kinetic Energy - The further the ball fall the more KE it has...until terminal velocity is reach, then KE would become constant. 
Potential Energy - Conversely to that of KE, the further the ball falls the less PE it will have. 

<em>Heat/Thermal Energy is technically also present due to the friction from the air resistance, but the transfer of energy between the air and ball is quite complex and not necessary important for basic physics.  
</em>
The question itself seem kind of vague and open ended, but I could just be viewing it the wrong way. 
Comment if you need more help! 
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A ball is traveling 24° above the horizontal at a speed of 12 m/s. What is the vertical component of its speed?
victus00 [196]

Answer:

4.88 m/s

Explanation:

Vertical component would be  12 * sin 24  =  4.88 m/s

Horizontal is   12 * cos 24

3 0
2 years ago
John accidentally drops his keys off the balcony at his apartment. John's friend Tony just happens to walk by at that moment and
EleoNora [17]

Explanation:

In order to find out if the keys will reach John or not, we can use the formula of projectile motion to find the maximum height reached by the keys:

H = V²Sin²θ/2g

where,

V = Launch Speed = 18 m/s

θ = Launch Angle = 40°

g = 9.8 m/s²

Therefore,

H = (18 m/s)²[Sin 40°]²/(2)(9.8 m/s²)

H = 6.83 m

Hence, the maximum height that can be reached by the projectile or the keys is greater than the height of John's Balcony(5.33 m).

Therefore, the keys will make it back to John.

7 0
3 years ago
A 3-kg rock is thrown upward with a force of 200 N at a location where the local gravitational acceleration is 9.79 m/s2 . Deter
expeople1 [14]

Answer: 56.87m/s^{2}

Explanation:

If we make an analysis of the net force F_{net} of the rock that was thrown upwards, we will have the following:

F_{net}=F_{up}-W  (1)

Where:

F_{up}=200N is the force with which the rock was thrown

W is the weight of the rock

Being the weight the relation between the mass m=3kg of the rock and the acceleration due gravity g=9.79m/s^{2} :

W=m.g=(3kg)(9.79m/s^{2}) (2)

W=29.37 N (3)

Substituting (3) in (1):

F_{net}=200N-29.37 N  (4)

F_{net}=170.63 N  (5) This is the net Force on the rock

On the other hand, we know this force is equal to the multiplication of the mass with the acceleration, according to Newton's 2nd Law:

F_{net}=m.a  (6)

Finding the acceleration a:

a=\frac{F_{net}}{m}  (7)

a=\frac{170.63 N}{3kg} (8)

Finally:

a=56.87m/s^{2}

3 0
3 years ago
A gas sample is confined within a chamber that has a movable piston. A small load is placed on the piston; and the system is all
timurjin [86]

Explanation:

It is given that,

Total weight of the piston, W = F = 70 N

Area of the piston, a=5\times 10^{-4}\ m^2

Let P is the pressure exerted on the piston by the gas. The force per unit area is called the pressure exerted pressure of the gas. Mathematically, it is given by :

P=\dfrac{F}{A}

P=\dfrac{70\ N}{5\times 10^{-4}\ m^2}

P=1.4\times 10^5\ Pa

We know that the atmospheric pressure is given by :

P_o=1.013\times 10^5\ Pa

So, the pressure is given by :

p=P+P_o

p=1.4\times 10^5+1.013\times 10^5

p=2.41\times 10^5\ Pa

Hence, this is the required solution.

7 0
3 years ago
the first s-wave reaches a seismic station 22 minutes after an earthquake occurred. how long did it take the first p-wave to rea
Naddik [55]

The time taken for the first p-wave to reach the same seismic station is approximately 13 minutes.

<h3>Time of travel of the P-wave</h3>

In rock, S waves generally travel about 60% the speed of P waves, and the S wave always arrives after the P wave.

<h3>Relationship between speed and time</h3>

v ∝ 1/t

v₁t₁ = v₂t₂

t₁/t₂ = v₂/v₁

t₁/t₂ = 0.6v₁/v₁

t₁/t₂ =  0.6

t₁ = 0.6t₂

t₁ = 0.6 x 22 mins

t₁ = 13.2 mins

Thus, the time taken for the first p-wave to reach the same seismic station is approximately 13 minutes.

Learn more about P-waves here: brainly.com/question/2552909

#SPJ1

7 0
2 years ago
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