1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kenny6666 [7]
3 years ago
12

The electrical charge of an atom as a whole is?

Physics
2 answers:
gayaneshka [121]3 years ago
8 0
<span>The electrical charge of an atom as a whole is?

Answer:</span><span>C. Neutral</span>

Natali5045456 [20]3 years ago
5 0
Im pretty sure its <span>C. Neutral.</span>
You might be interested in
In which case does viscosity play a dominant role? Case A: a typical bacterium (size ~ 1 mm1 mm and velocity ~ 20 mm/s20 mm/s) i
My name is Ann [436]

Answer:

Case A

Explanation:

given,

size of bacteria = 1 mm x 1 mm

velocity = 20 mm/s

size of the swimmer = 1.5 m x 1.5 m

velocity of swimmer = 3 m/s

Viscous force

F = \eta A \dfrac{dv}{dx}

for the bacteria

F = \eta \times 10^{-6}\times 20\times 10^{-3}

F =2\times 10^{-8} \eta\ N

for the swimmer

F = \eta \times 1.5^2\times 3

F =6.75 \eta\ N

from the above force calculation

In case B inertial force that represent mass is more than the inertial force in case of bacteria.

Viscous force is dominant in case of bacteria.

So, In Case A viscous force will be dominant.

5 0
3 years ago
Select the correct answer.
Gekata [30.6K]

Answer:

A.

Explanation:

an atom that has most of its mass is electrons.

6 0
3 years ago
What do you need to know to be able to determine how far a projectile travels horizontally?
Effectus [21]
As for me, there are two suitable answers for the question represented above and here is a short explanation why I consider these two to be correct : 
D. The horizontal velocity of the projectile and <span>B. The length of time before it lands 
</span>v_x = v*cos(x) [&#10;&#10;d_x = v_x(t) + ½at² -- this led me to answers! Hope everything is clear! Regards!<span>
</span>
5 0
3 years ago
A police car parked on the side of the highway emits a 1200 Hz sound that bounces off a vehicle farther down the highway and ret
emmasim [6.3K]

f' = frequency observed by the police car after sound reflected from the vehicle and comes back to police car = 1250 Hz

f = frequency emitted by the police car  = 1200 Hz

V = speed of sound = 340 m/s

v = speed of vehicle = ?

frequency observed by the police car is given as

f' = f (V + v)/(V - v)

inserting the values in the above equation

1250 = 1200 (340 + v)/(340 - v)

v = 6.9 m/s

4 0
3 years ago
Read 2 more answers
What happens to a mirror when a ray is directed at it
mixas84 [53]

Nothing happens to the mirror. 

However, if the ray is within some suitable range of
wavelengths, the ray is reflected from the mirror's surface.

3 0
3 years ago
Other questions:
  • A mining crew extracted two different types of minerals from underground. Then, they transferred the same amount of energy into
    11·2 answers
  • If one replaces the conducting cube with one that has positive charge carriers, in what direction does the induced electric fiel
    14·1 answer
  • Which are reactions that release energy? endothermic reactions exothermic reactions decomposition reactions
    8·1 answer
  • Electromagnetic force is present when electromagnetic fields
    6·2 answers
  • (b) Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a c
    12·2 answers
  • What is weight vs mass
    15·1 answer
  • Does the asteroid belt revolve around the sun?
    14·1 answer
  • Earth's curvature causes _____ heating of the surface by sun.<br> (one word)
    12·2 answers
  • By the end of the 19th century, more than half of the population believed in the presence of atoms.
    14·1 answer
  • Which is an electromagnetic wave A. The waves that heat a cup of water in a microwave oven B. A flag waving in the wind C. Turni
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!