Given :
Reem took a wire of length 10 cm. Her friend Nain took a wire of 5 cm of the same material and thickness both of them connected with wires as shown in the circuit given in figure. The current flowing in both the circuits is the same.
To Find :
Will the heat produced in both the cases be equal.
Solution :
Heat released is given by :
H = i²Rt
Here, R is resistance and is given by :
So,
Now, in the question every thing is constant except for the length of the wire and from above equation heat is directly proportional to the length of the wire.
So, heat produced by Reem's wire is more than Nain one.
Hence, this is the required solution.
During phase changes, energy changes are usually involved. For example, when solid dry ice vaporizes (physical change), carbon dioxide molecules absorb energy. Meanwhile, when liquid water becomes ice energy is released.
hope this helps :)
Answer:
Explanation:Advatages
1..Its takes precise reading accurate
2. it is moveable because of its small weight
3.It is easy to read and can be kept inside water
Disadvantages
1. It breaks easily because of its small size
2. If broken there can be risk of exposure to mercury chemicals.
Answer:
E₂ / E₁ = 521.64 / 5.95 =87.67
Explanation:
Let d be the distance covered inside electric field . Lt q be the magnitude of charge.
Force under field E₁ = q E₁
acceleration = qE₁/ m
d = 1/2 a t²
d = .5 ( qE₁ / m) x 32.3²
d = 521.64 ( qE₁ / m)
Similarly for return journey,
d = .5 x ( qE₂ / m) x 3.45²
d = 5.95x( qE₂ / m)
521.64 ( qE₁ / m) = 5.95x( qE₂ / m)
E₂ / E₁ = 521.64 / 5.95 =87.67
√10(√10) = √10^2
The root and the square cancels:
√10^2 = 10
10 is your answer
hope this helps
